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DAA - Cook’s Theorem
  • 时间:2024-11-05

Design and Analysis Cook’s Theorem


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Stephen Cook presented four theorems in his paper “The Complexity of Theorem Proving Procedures”. These theorems are stated below. We do understand that many unknown terms are being used in this chapter, but we don’t have any scope to discuss everything in detail.

Following are the four theorems by Stephen Cook −

Theorem-1

If a set S of strings is accepted by some non-deterministic Turing machine within polynomial time, then S is P-reducible to {DNF tautologies}.

Theorem-2

The following sets are P-reducible to each other in pairs (and hence each has the same polynomial degree of difficulty): {tautologies}, {DNF tautologies}, D3, {sub-graph pairs}.

Theorem-3

    For any TQ(k) of type Q, $mathbf{frac{T_{Q}(k)}{frac{sqrt{k}}{(log:k)^2}}}$ is unbounded

    There is a TQ(k) of type Q such that $T_{Q}(k)leqslant 2^{k(log:k)^2}$

Theorem-4

If the set S of strings is accepted by a non-deterministic machine within time T(n) = 2n, and if TQ(k) is an honest (i.e. real-time countable) function of type Q, then there is a constant K, so S can be recognized by a deterministic machine within time TQ(K8n).

    First, he emphasized the significance of polynomial time reducibipty. It means that if we have a polynomial time reduction from one problem to another, this ensures that any polynomial time algorithm from the second problem can be converted into a corresponding polynomial time algorithm for the first problem.

    Second, he focused attention on the class NP of decision problems that can be solved in polynomial time by a non-deterministic computer. Most of the intractable problems belong to this class, NP.

    Third, he proved that one particular problem in NP has the property that every other problem in NP can be polynomially reduced to it. If the satisfiabipty problem can be solved with a polynomial time algorithm, then every problem in NP can also be solved in polynomial time. If any problem in NP is intractable, then satisfiabipty problem must be intractable. Thus, satisfiabipty problem is the hardest problem in NP.

    Fourth, Cook suggested that other problems in NP might share with the satisfiabipty problem this property of being the hardest member of NP.

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