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Statistics - Negative Binomial Distribution
Negative binomial distribution is a probabipty distribution of number of occurences of successes and failures in a sequence of independent trails before a specific number of success occurs. Following are the key points to be noted about a negative binomial experiment.
The experiment should be of x repeated trials.
Each trail have two possible outcome, one for success, another for failure.
Probabipty of success is same on every trial.
Output of one trial is independent of output of another trail.
Experiment should be carried out until r successes are observed, where r is mentioned beforehand.
Negative binomial distribution probabipty can be computed using following:
Formula
${ f(x; r, P) = ^{x-1}C_{r-1} imes P^r imes (1-P)^{x-r} }$
Where −
${x}$ = Total number of trials.
${r}$ = Number of occurences of success.
${P}$ = Probabipty of success on each occurence.
${1-P}$ = Probabipty of failure on each occurence.
${f(x; r, P)}$ = Negative binomial probabipty, the probabipty that an x-trial negative binomial experiment results in the rth success on the xth trial, when the probabipty of success on each trial is P.
${^{n}C_{r}}$ = Combination of n items taken r at a time.
Example
Robert is a football player. His success rate of goal hitting is 70%. What is the probabipty that Robert hits his third goal on his fifth attempt?
Solution:
Here probabipty of success, P is 0.70. Number of trials, x is 5 and number of successes, r is 3. Using negative binomial distribution formula, let s compute the probabipty of hitting third goal in fifth attempt.
${ f(x; r, P) = ^{x-1}C_{r-1} imes P^r imes (1-P)^{x-r} \[7pt] imppes f(5; 3, 0.7) = ^4C_2 imes 0.7^3 imes 0.3^2 \[7pt] , = 6 imes 0.343 imes 0.09 \[7pt] , = 0.18522 }$
Thus probabipty of hitting third goal in fifth attempt is $ { 0.18522 }$.
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