- Moore & Mealy Machines
- DFA Minimization
- NDFA to DFA Conversion
- Non-deterministic Finite Automaton
- Deterministic Finite Automaton
- Automata Theory Introduction
- Automata Theory - Home
Classification of Grammars
Regular Grammar
- DFA Complement
- Pumping Lemma for Regular Grammar
- Constructing FA from RE
- Regular Sets
- Regular Expressions
Context-Free Grammars
- Pumping Lemma for CFG
- Greibach Normal Form
- Chomsky Normal Form
- CFG Simplification
- CFL Closure Properties
- Ambiguity in Grammar
- Context-Free Grammar Introduction
Pushdown Automata
- PDA & Parsing
- PDA & Context Free Grammar
- Pushdown Automata Acceptance
- Pushdown Automata Introduction
Turing Machine
- Linear Bounded Automata
- Semi-Infinite Tape Turing Machine
- Non-Deterministic Turing Machine
- Multi-Track Turing Machine
- Multi-tape Turing Machine
- Accepted & Decided Language
- Turing Machine Introduction
Decidability
- Post Correspondence Problem
- Rice Theorem
- Turing Machine Halting Problem
- Undecidable Language
- Language Decidability
Automata Theory Useful Resources
Selected Reading
- Who is Who
- Computer Glossary
- HR Interview Questions
- Effective Resume Writing
- Questions and Answers
- UPSC IAS Exams Notes
Construction of an FA from an RE
We can use Thompson s Construction to find out a Finite Automaton from a Regular Expression. We will reduce the regular expression into smallest regular expressions and converting these to NFA and finally to DFA.
Some basic RA expressions are the following −
Case 1 − For a regular expression ‘a’, we can construct the following FA −
Case 2 − For a regular expression ‘ab’, we can construct the following FA −
Case 3 − For a regular expression (a+b), we can construct the following FA −
Case 4 − For a regular expression (a+b)*, we can construct the following FA −
Method
Step 1 Construct an NFA with Null moves from the given regular expression.
Step 2 Remove Null transition from the NFA and convert it into its equivalent DFA.
Problem
Convert the following RA into its equivalent DFA − 1 (0 + 1)* 0
Solution
We will concatenate three expressions "1", "(0 + 1)*" and "0"
Now we will remove the ε transitions. After we remove the ε transitions from the NDFA, we get the following −
It is an NDFA corresponding to the RE − 1 (0 + 1)* 0. If you want to convert it into a DFA, simply apply the method of converting NDFA to DFA discussed in Chapter 1.
Finite Automata with Null Moves (NFA-ε)
A Finite Automaton with null moves (FA-ε) does transit not only after giving input from the alphabet set but also without any input symbol. This transition without input is called a null move.
An NFA-ε is represented formally by a 5-tuple (Q, ∑, δ, q0, F), consisting of
Q − a finite set of states
∑ − a finite set of input symbols
δ − a transition function δ : Q × (∑ ∪ {ε}) → 2Q
q0 − an initial state q0 ∈ Q
F − a set of final state/states of Q (F⊆Q).
The above (FA-ε) accepts a string set − {0, 1, 01}
Removal of Null Moves from Finite Automata
If in an NDFA, there is ϵ-move between vertex X to vertex Y, we can remove it using the following steps −
Find all the outgoing edges from Y.
Copy all these edges starting from X without changing the edge labels.
If X is an initial state, make Y also an initial state.
If Y is a final state, make X also a final state.
Problem
Convert the following NFA-ε to NFA without Null move.
Solution
Step 1 −
Here the ε transition is between q1 and q2, so let q1 is X and qf is Y.
Here the outgoing edges from qf is to qf for inputs 0 and 1.
Step 2 −
Now we will Copy all these edges from q1 without changing the edges from qf and get the following FA −
Step 3 −
Here q1 is an initial state, so we make qf also an initial state.
So the FA becomes −
Step 4 −
Here qf is a final state, so we make q1 also a final state.
So the FA becomes −
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