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- Power Developed by Synchronous Motor
- Equivalent Circuit and Power Factor of Synchronous Motor
- Working of 3-Phase Synchronous Motor
- Losses and Efficiency of 3-Phase Alternator
- Output Power of 3-Phase Alternator
- Armature Reaction in Synchronous Machines
- Working of 3-Phase Alternator
- Construction of Synchronous Machine
- Introduction to 3-Phase Synchronous Machines
- Methods of Starting 3-Phase Induction Motors
- Speed Regulation and Speed Control
- Characteristics of 3-Phase Induction Motor
- Three-Phase Induction Motor on Load
- Construction of Three-Phase Induction Motor
- Three-Phase Induction Motor
- Single-Phase Induction Motor
- Introduction to Induction Motor
- Applications of DC Machines
- Losses in DC Machines
- Types of DC Motors
- Back EMF in DC Motor
- Working Principle of DC Motor
- Types of DC Generators
- EMF Equation of DC Generator
- Working Principle of DC Generator
- Types of DC Machines
- Construction of DC Machines
- Types of Transformers
- Three-Phase Transformer
- Efficiency of Transformer
- Losses in a Transformer
- Transformer on DC
- Ideal and Practical Transformers
- Turns Ratio and Voltage Transformation Ratio
- EMF Equation of Transformer
- Construction of Transformer
- Electrical Transformer
- Fleming’s Left Hand and Right Hand Rules
- Concept of Induced EMF
- Faraday’s Laws of Electromagnetic Induction
- Rotating Electrical Machines
- Singly-Excited and Doubly Excited Systems
- Energy Stored in a Magnetic Field
- Electromechanical Energy Conversion
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Energy Stored in a Magnetic Field
In the previous chapter, we discussed that in an electromechanical energy conversion device, there is a medium of couppng between electrical and mechanical systems. In most of practical devices, magnetic field is used as the couppng medium. Therefore, an electromechanical energy conversion device comprises an electromagnetic system. Consequently, the energy stored in the couppng medium is in the form of the magnetic field. We can calculate the energy stored in the magnetic field of an electromechanical energy conversion system as described below.
Consider a coil having N turns of conductor wire wound around a magnetic core as shown in Figure-1. This coil is energized from a voltage source of v volts.
![Electromagnetic Circuit](/electrical_machines/images/electromagnetic_circuit.jpg)
By applying KVL, the appped voltage to the coil to given by,
$$mathrm{mathit{V:=:e:+:iR}cdot cdot cdot (1)}$$
Where,
e is induced EMF in the coil due to electromagnetic induction.
R is the resistance of the coil circuit.
$mathit{i}$ is the current flowing the coil.
The instantaneous power input to the electromagnetic system is given by,
$$mathrm{mathit{p}:=:mathit{Vi:=:ileft ( e+iR ight )}}$$
$$mathrm{Rightarrow mathit{p}:=:mathit{ie+ i^{mathrm{2}}}mathit{R}cdot cdot cdot (2)}$$
Now, let a direct voltage is appped to the circuit at time t = 0 and that at end of t = t1 seconds, and the current in the circuit has attained a value of I amperes. Then, during this time interval, the energy input the system is given by,
$$mathrm{mathit{W}_{in}:=:int_{0}^{t_{mathrm{1}}}:mathit{p:dt}}$$
$$mathrm{Rightarrow mathit{W}_{in}:=:int_{0}^{t_{mathrm{1}}}:mathit{ie:dt}:+:int_{0}^{t_{mathrm{1}}}mathit{i^{mathrm{2}}R:dt}cdot cdot cdot (3)}$$
From Equation-3, it is clear that the total input energy consists of two parts −
The first part is the energy stored in the magnetic field.
The second part is the energy dissipated due to electrical resistance of the coil.
Thus, the energy stored in the magnetic field of the system is,
$$mathrm{mathit{W}_{mathit{f}}:=:int_{0}^{t_{mathrm{1}}}:mathit{ie:dt}:cdot cdot cdot (4)}$$
According to Faraday’s law of electromagnetic induction, we have,
$$mathrm{mathit{e}:=:frac{mathit{dpsi }}{mathit{dt}}:=:frac{mathit{d}}{mathit{dt}}left ( mathit{Nphi } ight ):=:mathit{N}frac{mathit{dphi }}{mathit{dt}}cdot cdot cdot (5)}$$
Where, $psi$ is the magnetic flux pnkage and it is equal to $mathit{psi :=:Nphi }$.
$$mathrm{ herefore mathit{W_{f}}:=:int_{0}^{mathit{t_{mathrm{1}}}}frac{mathit{dpsi }}{mathit{dt}}mathit{i:dt}}$$
$$mathrm{Rightarrow mathit{W_{f}}:=:int_{0}^{psi_{mathrm{1}}}mathit{i:dpsi }cdot cdot cdot (6)}$$
Therefore, the equation (6) shows that the energy stored in the magnetic field is equal to the area between the ($psi -i$) curve (i.e., magnetization curve) for the electromagnetic system and the flux pnkage ($psi$) axis as shown in Figure-2.
![Magnetic Curve](/electrical_machines/images/magnetic_curve.jpg)
For a pnear electromagnetic system, the energy stored in the magnetic field is given by,
$$mathrm{mathit{W_{f}}:=:int_{0}^{mathit{psi _{mathrm{1}}}}mathit{idpsi }:=:int_{0}^{psi_{mathrm{1}} }frac{psi }{mathit{L}}mathit{dpsi }}$$
Where, $psi:=:mathit{Nphi }:=:mathit{Li}$ and L is the self-inductance of the coil.
$$mathrm{ herefore mathit{W_{f}}:=:frac{psi ^{mathrm{2}}}{2mathit{L}}:=:frac{1}{2}mathit{Li^{mathrm{2}}}cdot cdot cdot (7)}$$
Concept of Coenergy
Coenergy is an imaginary concept used to derive expressions for torque developed in an electromagnetic system. Thus, the coenergy has no physical significance in the system.
Basically, the coenergy is the area between the $psi -i$ curve and the current axis and is denoted by $mathit{W_{f}^{ }}$ as shown above in Figure-2.
Mathematically, the coenergy is given by,
$$mathrm{mathit{W_{f}^{ }}:=:int_{0}^{i}psi mathit{di}:=:int_{0}^{i}mathit{Li:di}}$$
$$mathrm{Rightarrow mathit{W_{f}^{ }}:=:frac{1}{2}mathit{Li^{mathrm{2}}}cdot cdot cdot (8)}$$
From equations (7) and (8), it is clear that for a pnear magnetic system, the energy stored in the magnetic field and the coenergy are equal.
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