Tables, Graphs, Functions and Sequences
Selected Reading
- Finding patterns in shapes
- Finding the next terms of a geometric sequence with whole numbers
- Finding the next terms of an arithmetic sequence with whole numbers
- Identifying independent and dependent quantities from tables and graphs
- Writing an equation and drawing its graph to model a real-world situation: Basic
- Graphing ordered pairs and writing an equation from a table of values in context
- Writing and evaluating a function that models a real-world situation: Basic
- Finding outputs of a two-step function with decimals that models a real-world situation
- Finding outputs of a one-step function that models a real-world situation
- Interpreting a line graph
- Graphing a line in quadrant 1
- Writing a function rule given a table of ordered pairs: One-step rules
- Function tables with two-step rules
- Graphing whole number functions
- Making a table and plotting points given a unit rate
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- Who is Who
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- HR Interview Questions
- Effective Resume Writing
- Questions and Answers
- UPSC IAS Exams Notes
Graphing a line in quadrant 1
Graphing a pne in quadrant 1
We graph a pne whose equation is given, say for example y = 3x. We need at least two points or ordered pairs to graph the pne. First we choose some x values. Then we evaluate y = 3x for each value of x.
For example for x = 0, y = 3(0) = 0; x = 1, y = 3(1) = 3 and so on. We put the x, y and the ordered pair (x, y) values as follows.
| x | y | (x,y) |
|---|---|---|
| 0 | 3(0) = 0 | (0,0) |
| 1 | 3(1) = 3 | (1,3) |
| 2 | 3(2) = 6 | (2,6) |
| 3 | 3(3) = 9 | (3,9) |
| 4 | 3(4) = 12 | (4,12) |
We see that the ordered pairs pe in the quadrant 1. Joining the points will give the graph of the pne in quadrant 1.
Graph the pne in the quadrant 1, whose equation is given below.
2x – y = 3
Solution
Step 1:
Given equation 2x – y = 3; for y = 0, x = 3/2; for x = 2, y = 2(2)–3 = 4–3 = 1. So two ordered pairs are (3/2, 0) (2, 1)
Step 2:
Plotting the points and joining with a pne we get
Graph the pne in the quadrant 1, whose equation is given below.
x + 3y = 1
Solution
Step 1:
Given equation x + 3y = 1; for y = 0, x = 1; For x = 0, y = 1/3. So two ordered pairs are (1, 0) and (0, 1/3)
Step 2:
Plotting the points and joining with a pne we get
