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DC Converters Solved Example
DC to DC Converters Solved Example
A step up chopper has an input voltage of 150V. The voltage output needed is 450V. Given, that the thyristor has a conducting time of 150μseconds. Calculate the chopping frequency.
Solution −
The chopping frequency (f)
$f=frac{1}{T}$
Where T – Chopping time period = $T_{ON}+T_{OFF}$
Given − $V_{S}=150V$$V_{0}=450V$ $T_{ON}=150mu sec$
$V_{0}=V_{Sleft ( frac{T}{T-T_{ON}} ight )}$
$450=150frac{T}{T-150^{-6}}$ $T=225mu sec$
Therfore, $f=frac{1}{225ast 10^{-6}}=4.44KHz$
The new voltage output, on condition that the operation is at constant frequency after the halving the pulse width.
Halving the pulse width gives −
$$T_{ON}=frac{150 imes 10^{-6}}{2}=75mu sec$$The frequency is constant thus,
$$f=4.44KHz$$ $$T=frac{1}{f}=150mu sec$$The voltage output is given by −
$$V_{0}=V_{S}left ( frac{T}{T-T_{ON}} ight )=150 imes left ( frac{150 imes 10^{-6}}{left ( 150-75 ight ) imes 10^{-6}} ight )=300Volts$$ Advertisements