- State Space Analysis
- Control Systems - State Space Model
- Control Systems - Controllers
- Control Systems - Compensators
- Control Systems - Nyquist Plots
- Control Systems - Polar Plots
- Construction of Bode Plots
- Control Systems - Bode Plots
- Frequency Response Analysis
- Construction of Root Locus
- Control Systems - Root Locus
- Control Systems - Stability Analysis
- Control Systems - Stability
- Steady State Errors
- Time Domain Specifications
- Response of Second Order System
- Response of the First Order System
- Time Response Analysis
- Signal Flow Graphs
- Block Diagram Reduction
- Block Diagram Algebra
- Control Systems - Block Diagrams
- Electrical Analogies of Mechanical Systems
- Modelling of Mechanical Systems
- Mathematical Models
- Control Systems - Feedback
- Control Systems - Introduction
- Control Systems - Home
Control Systems Useful Resources
Selected Reading
- Who is Who
- Computer Glossary
- HR Interview Questions
- Effective Resume Writing
- Questions and Answers
- UPSC IAS Exams Notes
Frequency Response Analysis
We have already discussed time response analysis of the control systems and the time domain specifications of the second order control systems. In this chapter, let us discuss the frequency response analysis of the control systems and the frequency domain specifications of the second order control systems.
What is Frequency Response?
The response of a system can be partitioned into both the transient response and the steady state response. We can find the transient response by using Fourier integrals. The steady state response of a system for an input sinusoidal signal is known as the frequency response. In this chapter, we will focus only on the steady state response.
If a sinusoidal signal is appped as an input to a Linear Time-Invariant (LTI) system, then it produces the steady state output, which is also a sinusoidal signal. The input and output sinusoidal signals have the same frequency, but different ampptudes and phase angles.
Let the input signal be −
$$r(t)=Asin(omega_0t)$$
The open loop transfer function will be −
$$G(s)=G(jomega)$$
We can represent $G(jomega)$ in terms of magnitude and phase as shown below.
$$G(jomega)=|G(jomega)| angle G(jomega)$$
Substitute, $omega = omega_0$ in the above equation.
$$G(jomega_0)=|G(jomega_0)| angle G(jomega_0)$$
The output signal is
$$c(t)=A|G(jomega_0)|sin(omega_0t + angle G(jomega_0))$$
The ampptude of the output sinusoidal signal is obtained by multiplying the ampptude of the input sinusoidal signal and the magnitude of $G(jomega)$ at $omega = omega_0$.
The phase of the output sinusoidal signal is obtained by adding the phase of the input sinusoidal signal and the phase of $G(jomega)$ at $omega = omega_0$.
Where,
A is the ampptude of the input sinusoidal signal.
ω0 is angular frequency of the input sinusoidal signal.
We can write, angular frequency $omega_0$ as shown below.
$$omega_0=2pi f_0$$
Here, $f_0$ is the frequency of the input sinusoidal signal. Similarly, you can follow the same procedure for closed loop control system.
Frequency Domain Specifications
The frequency domain specifications are resonant peak, resonant frequency and bandwidth.
Consider the transfer function of the second order closed loop control system as,
$$T(s)=frac{C(s)}{R(s)}=frac{omega_n^2}{s^2+2deltaomega_ns+omega_n^2}$$
Substitute, $s = jomega$ in the above equation.
$$T(jomega)=frac{omega_n^2}{(jomega)^2+2deltaomega_n(jomega)+omega_n^2}$$
$$Rightarrow T(jomega)=frac{omega_n^2}{-omega^2+2jdeltaomegaomega_n+omega_n^2}=frac{omega_n^2}{omega_n^2left ( 1-frac{omega^2}{omega_n^2}+frac{2jdeltaomega}{omega_n} ight )}$$
$$Rightarrow T(jomega)=frac{1}{left ( 1-frac{omega^2}{omega_n^2} ight )+jleft ( frac{2deltaomega}{omega_n} ight )}$$
Let, $frac{omega}{omega_n}=u$ Substitute this value in the above equation.
$$T(jomega)=frac{1}{(1-u^2)+j(2delta u)}$$
Magnitude of $T(jomega)$ is -
$$M=|T(jomega)|=frac{1}{sqrt {(1-u^2)^2+(2delta u)^2}}$$
Phase of $T(jomega)$ is -
$$angle T(jomega)=-tan^{-1}left( frac{2delta u}{1-u^2} ight )$$
Resonant Frequency
It is the frequency at which the magnitude of the frequency response has peak value for the first time. It is denoted by $omega_r$. At $omega = omega_r$, the first derivate of the magnitude of $T(jomega)$ is zero.
Differentiate $M$ with respect to $u$.
$$frac{ ext{d}M}{ ext{d}u}=-frac{1}{2}left [ (1-u^2)^2+(2delta u)^2 ight ]^{frac{-3}{2}} left [2(1-u^2)(-2u)+2(2delta u)(2delta) ight ]$$
$$Rightarrow frac{ ext{d}M}{ ext{d}u}=-frac{1}{2}left [ (1-u^2)^2+(2delta u)^2 ight ]^{frac{-3}{2}} left [4u(u^2-1 +2delta^2) ight ]$$
Substitute, $u=u_r$ and $frac{ ext{d}M}{ ext{d}u}==0$ in the above equation.
$$0=-frac{1}{2}left [ (1-u_r^2)^2+(2delta u_r)^2 ight ]^{-frac{3}{2}}left [ 4u_r(u_r^2-1 +2delta^2) ight ]$$
$$Rightarrow 4u_r(u_r^2-1 +2delta^2)=0$$
$$Rightarrow u_r^2-1+2delta^2=0$$
$$Rightarrow u_r^2=1-2delta^2$$
$$Rightarrow u_r=sqrt{1-2delta^2}$$
Substitute, $u_r=frac{omega_r}{omega_n}$ in the above equation.
$$frac{omega_r}{omega_n}=sqrt{1-2delta^2}$$
$$Rightarrow omega_r=omega_n sqrt{1-2delta^2}$$
Resonant Peak
It is the peak (maximum) value of the magnitude of $T(jomega)$. It is denoted by $M_r$.
At $u = u_r$, the Magnitude of $T(jomega)$ is -
$$M_r=frac{1}{sqrt{(1-u_r^2)^2+(2delta u_r)^2}}$$
Substitute, $u_r = sqrt{1 − 2delta^2}$ and $1 − u_r^2 = 2delta^2$ in the above equation.
$$M_r=frac{1}{sqrt{(2delta^2)^2+(2delta sqrt{1-2delta^2})^2}}$$
$$Rightarrow M_r=frac{1}{2delta sqrt {1-delta^2}}$$
Resonant peak in frequency response corresponds to the peak overshoot in the time domain transient response for certain values of damping ratio $delta$. So, the resonant peak and peak overshoot are correlated to each other.
Bandwidth
It is the range of frequencies over which, the magnitude of $T(jomega)$ drops to 70.7% from its zero frequency value.
At $omega = 0$, the value of $u$ will be zero.
Substitute, $u = 0$ in M.
$$M=frac{1}{sqrt {(1-0^2)^2+(2delta(0))^2}}=1$$
Therefore, the magnitude of $T(jomega)$ is one at $omega = 0$.
At 3-dB frequency, the magnitude of $T(jomega)$ will be 70.7% of magnitude of $T(jomega)$ at $omega = 0$.
i.e., at $omega = omega_B, M = 0.707(1) = frac{1}{sqrt{2}}$
$$Rightarrow M=frac{1}{sqrt{2}}=frac{1}{sqrt{(1-u_b^2)^2+(2delta u_b)^2}}$$
$$Rightarrow 2=(1-u_b^2)^2+(2delta)^2 u_b^2$$
Let, $u_b^2=x$
$$Rightarrow 2=(1-x)^2+(2delta)^2 x$$
$$Rightarrow x^2+(4delta^2-2)x-1=0$$
$$Rightarrow x=frac{-(4delta^2 -2)pm sqrt{(4delta^2-2)^2+4}}{2}$$
Consider only the positive value of x.
$$x=1-2delta^2+sqrt {(2delta^2-1)^2+1}$$
$$Rightarrow x=1-2delta^2+sqrt {(2-4delta^2+4delta^4)}$$
Substitute, $x=u_b^2=frac{omega_b^2}{omega_n^2}$
$$frac{omega_b^2}{omega_n^2}=1-2delta^2+sqrt {(2-4delta^2+4delta^4)}$$
$$Rightarrow omega_b=omega_n sqrt {1-2delta^2+sqrt {(2-4delta^2+4delta^4)}}$$
Bandwidth $omega_b$ in the frequency response is inversely proportional to the rise time $t_r$ in the time domain transient response.
Advertisements