- Word Problem Involving Fractions and Division
- Modeling Division of a Whole Number by a Fraction
- Fact Families for Multiplication and Division of Fractions
- Fraction Division
- Division Involving a Whole Number and a Fraction
- The Reciprocal of a Number
- Word Problem Involving Fractions and Multiplication
- Multiplication of 3 Fractions
- Modeling Multiplication of Proper Fractions
- Determining if a Quantity is Increased or Decreased When Multiplied by a Fraction
- Product of a Fraction and a Whole Number Problem Type 2
- Fraction Multiplication
- Introduction to Fraction Multiplication
- Product of a Fraction and a Whole Number: Problem Type 1
- Product of a Unit Fraction and a Whole Number
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Fraction Multippcation
Rules for fraction multippcation
To get the product of two fractions
We multiply the numerators.
We multiply the denominators.
If required, we cross cancel or simppfy before multiplying.
In such a case, we get a fraction in lowest terms.
Example
Multiply $frac{4}{5}$ × $frac{7}{9}$
Solution
Step 1:
Multiply the numerators and denominators of both fractions as follows.
$frac{4}{5}$ × $frac{7}{9}$ = $frac{(4 × 7)}{(5 × 9)}$ = $frac{28}{45}$
Step 2:
So, $frac{4}{5}$ × $frac{7}{9}$ = $frac{28}{45}$
Multiply $frac{4}{5}$ × $frac{10}{16}$ and write the answer as a fraction in simplest form
Solution
Step 1:
We multiply the numerators and denominators of both fractions as follows.
$frac{4}{5}$ × $frac{10}{16}$ = $frac{(4 × 10)}{(5 × 16)}$ = $frac{40}{80}$
Step 2:
Dividing numerator and denominator with the gcf of 40 and 80 which is 40.
So, $frac{40÷40}{80÷40}$ = $frac{1}{2}$
Step 3:
$frac{4}{5}$ × $frac{10}{16}$ = $frac{1}{2}$
This is the answer as a fraction in simplest form.
Multiply $frac{3}{4}$ × $frac{12}{15}$ and write the answer as a fraction in simplest form
Solution
Step 1:
We cross cancel 3 and 15 diagonally; we also cross cancel 4 and 12 diagonally.
$frac{3}{4}$ × $frac{12}{15}$ = $frac{1}{1}$ × $frac{3}{5}$
Step 2:
We multiply the numerators. Then we multiply the denominators.
$frac{1}{1}$ × $frac{3}{5}$ = $frac{(1 × 3)}{(1 × 5)}$ = $frac{3}{5}$
Step 3:
So $frac{3}{4}$ × $frac{12}{15}$= $frac{3}{5}$
This is already in simplest form.