PostgreSQL - INSERT Query

The PostgreSQL INSERT INTO statement allows one to insert new rows into a table. One can insert a single row at a time or several rows as a result of a query.

Syntax

Basic syntax of INSERT INTO statement is as follows −

INSERT INTO TABLE_NAME (column1, column2, column3,...columnN)
VALUES (value1, value2, value3,...valueN);

Here, column1, column2,...columnN are the names of the columns in the table into which you want to insert data.

The target column names can be psted in any order. The values suppped by the VALUES clause or query are associated with the exppcit or imppcit column pst left-to-right.

You may not need to specify the column(s) name in the SQL query if you are adding values for all the columns of the table. However, make sure the order of the values is in the same order as the columns in the table. The SQL INSERT INTO syntax would be as follows −

INSERT INTO TABLE_NAME VALUES (value1,value2,value3,...valueN);

Output

The following table summarizes the output messages and their meaning −

Examples

Let us create COMPANY table in testdb as follows −

CREATE TABLE COMPANY(
   ID INT PRIMARY KEY     NOT NULL,
   NAME           TEXT    NOT NULL,
   AGE            INT     NOT NULL,
   ADDRESS        CHAR(50),
   SALARY         REAL,
   JOIN_DATE	  DATE
);

The following example inserts a row into the COMPANY table −

INSERT INTO COMPANY (ID,NAME,AGE,ADDRESS,SALARY,JOIN_DATE) VALUES (1,  Paul , 32,  Capfornia , 20000.00, 2001-07-13 );

The following example is to insert a row; here salary column is omitted and therefore it will have the default value −

INSERT INTO COMPANY (ID,NAME,AGE,ADDRESS,JOIN_DATE) VALUES (2,  Allen , 25,  Texas ,  2007-12-13 );

The following example uses the DEFAULT clause for the JOIN_DATE column rather than specifying a value −

INSERT INTO COMPANY (ID,NAME,AGE,ADDRESS,SALARY,JOIN_DATE) VALUES (3,  Teddy , 23,  Norway , 20000.00, DEFAULT );

The following example inserts multiple rows using the multirow VALUES syntax −

INSERT INTO COMPANY (ID,NAME,AGE,ADDRESS,SALARY,JOIN_DATE) VALUES (4,  Mark , 25,  Rich-Mond  , 65000.00,  2007-12-13  ), (5,  David , 27,  Texas , 85000.00,  2007-12-13 );

All the above statements would create the following records in COMPANY table. The next chapter will teach you how to display all these records from a table.

ID        NAME        AGE        ADDRESS     SALARY	  JOIN_DATE
----      ----------  -----      ----------  -------      --------
1         Paul        32         Capfornia  20000.0      2001-07-13
2         Allen       25         Texas                    2007-12-13
3         Teddy       23         Norway      20000.0
4         Mark        25         Rich-Mond   65000.0      2007-12-13
5         David       27         Texas       85000.0      2007-12-13