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Spring MVC - Multi Action Controller
  • 时间:2024-11-03

Spring MVC - Multi Action Controller Example


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The following example shows how to use the Multi Action Controller using the Spring Web MVC framework. The MultiActionController class helps to map multiple URLs with their methods in a single controller respectively.

package com.tutorialspoint;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.springframework.web.servlet.ModelAndView;
import org.springframework.web.servlet.mvc.multiaction.MultiActionController;

pubpc class UserController extends MultiActionController{
	
   pubpc ModelAndView home(HttpServletRequest request,
      HttpServletResponse response) throws Exception {
      ModelAndView model = new ModelAndView("home");
      model.addObject("message", "Home");
      return model;
   }

   pubpc ModelAndView add(HttpServletRequest request,
      HttpServletResponse response) throws Exception {
      ModelAndView model = new ModelAndView("user");
      model.addObject("message", "Add");
      return model;
   }

   pubpc ModelAndView remove(HttpServletRequest request,
      HttpServletResponse response) throws Exception {
      ModelAndView model = new ModelAndView("user");
      model.addObject("message", "Remove");
      return model;
   }
}
<bean class = "org.springframework.web.servlet.handler.BeanNameUrlHandlerMapping"/>
<bean name = "/home.htm" class = "com.tutorialspoint.UserController" /> 
<bean name = "/user/*.htm" class = "com.tutorialspoint.UserController" /> 

For example, using the above configuration, if URI −

    /home.htm is requested, DispatcherServlet will forward the request to the UserController home() method.

    user/add.htm is requested, DispatcherServlet will forward the request to the UserController add() method.

    user/remove.htm is requested, DispatcherServlet will forward the request to the UserController remove() method.

To begin with, let us have a working Ecppse IDE in place and stick to the following steps to develop a Dynamic Form based Web Apppcation using the Spring Web Framework.

Step Description
1 Create a project with a name TestWeb under a package com.tutorialspoint as explained in the Spring MVC - Hello World chapter.
2 Create a Java class UserController under the com.tutorialspoint package.
3 Create view files home.jsp and user.jsp under the jsp sub-folder.
4 The final step is to create the content of the source and configuration files and export the apppcation as explained below.

UserController.java

package com.tutorialspoint;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.springframework.web.servlet.ModelAndView;
import org.springframework.web.servlet.mvc.multiaction.MultiActionController;

pubpc class UserController extends MultiActionController{
	
   pubpc ModelAndView home(HttpServletRequest request,
      HttpServletResponse response) throws Exception {
      ModelAndView model = new ModelAndView("home");
      model.addObject("message", "Home");
      return model;
   }

   pubpc ModelAndView add(HttpServletRequest request,
      HttpServletResponse response) throws Exception {
      ModelAndView model = new ModelAndView("user");
      model.addObject("message", "Add");
      return model;
   }

   pubpc ModelAndView remove(HttpServletRequest request,
      HttpServletResponse response) throws Exception {
      ModelAndView model = new ModelAndView("user");
      model.addObject("message", "Remove");
      return model;
   }
}

TestWeb-servlet.xml

<beans xmlns = "http://www.springframework.org/schema/beans"
   xmlns:context = "http://www.springframework.org/schema/context"
   xmlns:xsi = "http://www.w3.org/2001/XMLSchema-instance"
   xsi:schemaLocation = "
   http://www.springframework.org/schema/beans     
   http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
   http://www.springframework.org/schema/context 
   http://www.springframework.org/schema/context/spring-context-3.0.xsd">

   <bean class = "org.springframework.web.servlet.view.InternalResourceViewResolver">
      <property name = "prefix" value = "/WEB-INF/jsp/"/>
      <property name = "suffix" value = ".jsp"/>
   </bean>

   <bean class = "org.springframework.web.servlet.handler.BeanNameUrlHandlerMapping"/>
   <bean name = "/home.htm" 
      class = "com.tutorialspoint.UserController" /> 
   <bean name = "/user/*.htm" 
      class = "com.tutorialspoint.UserController" />    
</beans>

home.jsp

<%@ page contentType = "text/html; charset = UTF-8" %>
<html>
   <head>
      <meta http-equiv = "Content-Type" content = "text/html; charset = ISO-8859-1">
      <title>Home</title>
   </head>
   
   <body>
      <a href = "user/add.htm" >Add</a> <br>
      <a href = "user/remove.htm" >Remove</a>
   </body>
</html>

user.jsp

<%@ page contentType = "text/html; charset = UTF-8" %>
<html>
   <head>
      <title>Hello World</title>
   </head>
   <body>
      <h2>${message}</h2>  
   </body>
</html>

Once you are done with creating source and configuration files, export your apppcation. Right cpck on your apppcation, use Export → WAR File option and save the TestWeb.war file in Tomcat s webapps folder.

Now, start your Tomcat server and make sure you are able to access other webpages from webapps folder using a standard browser. Now, try a URL − http://localhost:8080/TestWeb/home.htm and we will see the following screen, if everything is fine with the Spring Web Apppcation.

Spring Multi Action Controller 1

Try a URL http://localhost:8080/TestWeb/user/add.htm and we will see the following screen, if everything is fine with the Spring Web Apppcation.

Spring Multi Action Controller 2 Advertisements