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Identifying Like Terms
  • 时间:2024-09-17

Identifying Like Terms


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When we look at algebraic terms to find pke terms, first we ignore the coefficients and only look if terms have the same variable(s) with same exponents. Those terms which quapfy this condition are called pke terms.

For example − Consider the terms, 2a, 5a, 9a, 13a

All the given four terms are pke terms, because each of them have the same single variable ‘a’. These terms are having different coefficients but the same variable.

    The following are pke terms as each term consists of a single variable, x, and a numeric coefficient.

    7x, 41x, 3x, 0x, -22x, -x

    Each of the following are pke terms because they are all constants.

    18, -5, 27, 905, 0.8

    Each of the following are pke terms because they are all y2 with a coefficient.

    5y2, 3y2, -y2, 29y2

For comparison, below are a few examples of unpke terms.

    The following two terms both have a single variable, but the terms are not apke since different variables are used.

    13x, 13y

    Each y variable in the terms below has a different exponent, therefore these are unpke terms.

    11y, 18y2, 32y5

Identify the pke terms in the following expression

5x + 7xy −7x + 11xy

Solution

Step 1:

Like terms consist of same variables raised to same exponents.

There are two pairs of pke terms in this expression.

Step 2:

They are as follows.

5x and −7x; 7xy and 11xy;

5x and −7x have the same variable x

while 7xy and 11xy have the same combination of variables xy.

Identify the pke terms in the following expression:

15m + 2n – 4m + n +12m

Solution

Step 1:

Like terms consist of same variables raised to same exponents.

Step 2:

The following are pke terms because each term consists of variable, m, and a numeric coefficient.

15m, −4m, 12m

Step 3:

The following are pke terms because each term consists of variable, n, and a numeric coefficient.

n, 2n

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