Perimeter and Area of Polygons
Selected Reading
- Finding the perimeter or area of a rectangle in the coordinate plane
- Area of a trapezoid
- Area of a parallelogram
- Area involving rectangles and triangles
- Finding the area of a trapezoid on a grid by using triangles and rectangles
- Area of a triangle
- Finding the area of a right triangle or its corresponding rectangle
- Finding the area of a right triangle on a grid
- Area between two rectangles
- Area of a piecewise rectangular figure
- Finding the side length of a rectangle given its perimeter or area
- Word problem involving the area of a square or a rectangle
- Areas of rectangles with the same perimeter
- Distinguishing between the area and perimeter of a rectangle
- Area of a rectangle involving fractions
- Perimeter of a piecewise rectangular figure
- Finding the missing length in a figure
- Sides of polygons having the same perimeter
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- UPSC IAS Exams Notes
Perimeter of a piecewise rectangular figure
Perimeter of a piecewise rectangular figure
In this lesson, we find the perimeter of given piecewise rectangular figures.
We are given piecewise rectangular figures with some measurements while some other ones are missing. We first find these missing lengths. In these figures, it is assumed that all intersecting sides meet in right angles. It is noted that opposite sides of a rectangle are parallel and equal in length while calculating the missing lengths. We also sppt the given figure into two rectangles for same purpose.
Once the missing lengths are found, adding up the length along the outer boundary of the given figure gives the perimeter of the given figure.
Find the perimeter of the following figure. Notice that some length is not given. Assume that all intersecting sides meet at right angles.
Solution
Step 1:
Missing lengths 7 – 3 = 4 cm; 5 – 2 = 3 cm
Step 2:
Perimeter of given figure = 5 + 7 + 2 + 4 + 3 + 3 = 24 cm
Find the perimeter of the following figure. Notice that some length is not given. Assume that all intersecting sides meet at right angles.
Solution
Step 1:
Missing lengths 60 – 40 = 20 mm; 30 + 15 = 45 mm
Step 2:
Perimeter of given figure = 45 + 60 + 15 + 40 + 30 + 20 = 210 mm
Opposite sides of rectangles are of same length.
Now we can find the perimeter of the figure by adding all lengths.