- Fractional Part of a Circle
- Word Problem Involving Add or Subtract Fractions With Different Denominators
- Add or Subtract Fractions With Different Denominators Advanced
- Addition or Subtraction of Fractions With Different Denominators
- Addition or Subtraction of Unit Fractions
- Finding the LCD of Two Fractions
- Add or Subtract Fractions With the Same Denominator and Simplification
- Add or Subtract Fractions With the Same Denominator
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Addition or Subtraction of Unit Fractions
A unit fraction is a fraction where the numerator is always one and the denominator is a positive integer. Addition or subtraction of unit fractions can be of two types; one, where the denominators are same; two, where the denominators are different.
When the unit fractions have pke denominators, we add the numerators and put the result over the common denominator to get the answer.
When the unit fractions have unpke or different denominators, we first find the LCD of the fractions. Then we rewrite all unit fractions to equivalent fractions using the LCD as the denominator. Now that all denominators are apke, we add the numerators and put the result over the common denominator to get the answer.
When the unit fractions have pke denominators, we subtract the numerators and put the result over the common denominator to get the answer.
When the unit fractions have unpke or different denominators, we first find the LCD of the fractions. Then we rewrite all unit fractions to equivalent fractions using the LCD as the denominator. Now that all denominators are apke, we subtract the numerators and put the result over the common denominator to get the answer.
Add $frac{1}{3}$ + $frac{1}{9}$
Solution
Step 1:
Add $frac{1}{3}$ + $frac{1}{9}$
Here the denominators are different. As 9 is a multiple of 3, the LCD is 9 itself.
Step 2:
Rewriting
$frac{1}{3}$ + $frac{1}{9}$ = $frac{(1×3)}{(3×3)}$ + $frac{1}{9}$ = $frac{3}{9}$ + $frac{1}{9}$
Step 3:
As the denominators have become equal
$frac{3}{9}$ + $frac{1}{9}$ = $frac{(3+1)}{9}$ = $frac{4}{9}$
Step 4:
So, $frac{1}{3}$ + $frac{1}{9}$ = $frac{4}{9}$
Subtract $frac{1}{9}$ − $frac{1}{12}$
Solution
Step 1:
Subtract $frac{1}{9}$ − $frac{1}{12}$
Here the denominators are different. The LCD of the fractions is 36.
Step 2:
Rewriting
$frac{1}{9}$ − $frac{1}{12}$ = $frac{(1×4)}{(9×4)}$ − $frac{(1×3)}{(12×3)}$ = $frac{4}{36}$ − $frac{3}{36}$
Step 3:
As the denominators have become equal
$frac{4}{36}$ − $frac{3}{36}$ = $frac{(4−3)}{36}$ = $frac{1}{36}$
Step 4:
So, $frac{1}{9}$ − $frac{1}{12}$ = $frac{1}{36}$