Radar Systems - Overview

RADAR is an electromagnetic based detection system that works by radiating electromagnetic waves and then studying the echo or the reflected back waves.

The full form of RADAR is RAdio Detection And Ranging. Detection refers to whether the target is present or not. The target can be stationary or movable, i.e., non-stationary. Ranging refers to the distance between the Radar and the target.

Radars can be used for various apppcations on ground, on sea and in space. The apppcations of Radars are psted below.

Controlpng the Air Traffic

Ship safety

Sensing the remote places

Miptary apppcations

In any apppcation of Radar, the basic principle remains the same. Let us now discuss the principle of radar.

Basic Principle of Radar

Radar is used for detecting the objects and finding their location. We can understand the basic principle of Radar from the following figure.

As shown in the figure, Radar mainly consists of a transmitter and a receiver. It uses the same Antenna for both transmitting and receiving the signals. The function of the transmitter is to transmit the Radar signal in the direction of the target present.

Target reflects this received signal in various directions. The signal, which is reflected back towards the Antenna gets received by the receiver.

Terminology of Radar Systems

Following are the basic terms, which are useful in this tutorial.

Range

Pulse Repetition Frequency

Maximum Unambiguous Range

Minimum Range

Now, let us discuss about these basic terms one by one.

Range

The distance between Radar and target is called Range of the target or simply range, R. We know that Radar transmits a signal to the target and accordingly the target sends an echo signal to the Radar with the speed of pght, C.

Let the time taken for the signal to travel from Radar to target and back to Radar be ‘T’. The two way distance between the Radar and target will be 2R, since the distance between the Radar and the target is R.

Now, the following is the formula for Speed.

$$Speed= frac{Distance}{Time}$$

$$Rightarrow Distance=Speed imes Time$$

$$Rightarrow 2R=C imes T$$

$$R=frac{CT}{2}:::::Equation:1$$

We can find the range of the target by substituting the values of C & T in Equation 1.

Pulse Repetition Frequency

Radar signals should be transmitted at every clock pulse. The duration between the two clock pulses should be properly chosen in such a way that the echo signal corresponding to present clock pulse should be received before the next clock pulse. A typical Radar wave form is shown in the following figure.

As shown in the figure, Radar transmits a periodic signal. It is having a series of narrow rectangular shaped pulses. The time interval between the successive clock pulses is called pulse repetition time, $T_P$.

The reciprocal of pulse repetition time is called pulse repetition frequency, $f_P$. Mathematically, it can be represented as

Therefore, pulse repetition frequency is nothing but the frequency at which Radar transmits the signal.

Maximum Unambiguous Range

We know that Radar signals should be transmitted at every clock pulse. If we select a shorter duration between the two clock pulses, then the echo signal corresponding to present clock pulse will be received after the next clock pulse. Due to this, the range of the target seems to be smaller than the actual range.

So, we have to select the duration between the two clock pulses in such a way that the echo signal corresponding to present clock pulse will be received before the next clock pulse starts. Then, we will get the true range of the target and it is also called maximum unambiguous range of the target or simply, maximum unambiguous range.

Substitute, $R=R_{un}$ and $T=T_P$ in Equation 1.

$$R_{un}=frac{CT_P}{2}:::::Equation:3$$

From Equation 2, we will get the pulse repetition time, $T_P$ as the reciprocal of pulse repetition frequency, $f_P$. Mathematically, it can be represented as

$$T_P=frac{1}{f_P}:::::Equation:4$$

Substitute, Equation 4 in Equation 3.

$$R_{un}=frac{Cleft ( frac{1}{f_P} ight )}{2}$$

$$R_{un}=frac{C}{2f_P}:::::Equation:5$$

We can use either Equation 3 or Equation 5 for calculating maximum unambiguous range of the target.

We will get the value of maximum unambiguous range of the target, $R_{un}$ by substituting the values of $C$ and $T_P$ in Equation 3.

Similarly, we will get the value of maximum unambiguous range of the target, $R_{un}$ by substituting the values of $C$ and $f_P$ in Equation 5.

Minimum Range

We will get the minimum range of the target, when we consider the time required for the echo signal to receive at Radar after the signal being transmitted from the Radar as pulse width. It is also called the shortest range of the target.

Substitute, $R=R_{min}$ and $T= au$ in Equation 1.

$$R_{min}=frac{C au}{2}:::::Equation:6$$

We will get the value of minimum range of the target, $R_{min}$ by substituting the values of $C$ and $ au$ in Equation 6.

Radar Systems - Range Equation

Radar range equation is useful to know the range of the target theoretically. In this chapter, we will discuss the standard form of Radar range equation and then will discuss about the two modified forms of Radar range equation.

We will get those modified forms of Radar range equation from the standard form of Radar range equation. Now, let us discuss about the derivation of the standard form of Radar range equation.

Derivation of Radar Range Equation

The standard form of Radar range equation is also called as simple form of Radar range equation. Now, let us derive the standard form of Radar range equation.

We know that power density is nothing but the ratio of power and area. So, the power density, $P_{di}$ at a distance, R from the Radar can be mathematically represented as −

$$P_{di}=frac{P_t}{4pi R^2}:::::Equation:1$$

Where,

The above power density is vapd for an isotropic Antenna. In general, Radars use directional Antennas. Therefore, the power density, $P_{dd}$ due to directional Antenna will be −

$$P_{dd}=frac{P_tG}{4pi R^2}:::::Equation:2$$

Target radiates the power in different directions from the received input power. The amount of power, which is reflected back towards the Radar depends on its cross section. So, the power density $P_{de}$ of echo signal at Radar can be mathematically represented as −

$$P_{de}=P_{dd}left (frac{sigma}{4pi R^2} ight ):::::Equation:3$$ Substitute, Equation 2 in Equation 3.

$$P_{de}=left (frac{P_tG}{4pi R^2} ight )left (frac{sigma}{4pi R^2} ight ):::::Equation:4$$

The amount of power, $P_r$ received by the Radar depends on the effective aperture, $A_e$ of the receiving Antenna.

$$P_r=P_{de}A_e:::::Equation:5$$

Substitute, Equation 4 in Equation 5.

$$P_r=left (frac{P_tG}{4pi R^2} ight )left (frac{sigma}{4pi R^2} ight )A_e$$

$$Rightarrow P_r=frac{P_tGsigma A_e}{left (4pi ight )^2 R^4}$$

$$Rightarrow R^4=frac{P_tGsigma A_e}{left (4pi ight )^2 P_r}$$

$$Rightarrow R=left [frac{P_tGsigma A_e}{left (4pi ight )^2 P_r} ight ]^{1/4}:::::Equation:6$$

Standard Form of Radar Range Equation

If the echo signal is having the power less than the power of the minimum detectable signal, then Radar cannot detect the target since it is beyond the maximum pmit of the Radar s range.

Therefore, we can say that the range of the target is said to be maximum range when the received echo signal is having the power equal to that of minimum detectable signal. We will get the following equation, by substituting $R=R_{Max}$ and $P_r=S_{min}$ in Equation 6.

$$R_{Max}=left [frac{P_tGsigma A_e}{left (4pi ight )^2 S_{min}} ight ]^{1/4}:::::Equation:7$$

Equation 7 represents the standard form of Radar range equation. By using the above equation, we can find the maximum range of the target.

Modified Forms of Radar Range Equation

We know the following relation between the Gain of directional Antenna, $G$ and effective aperture, $A_e$.

$$G=frac{4pi A_e}{lambda^2}:::::Equation:8$$

Substitute, Equation 8 in Equation 7.

$$R_{Max}=left [ frac{P_tsigma A_e}{left ( 4pi ight )^2S_{min}}left ( frac{4pi A_e}{lambda^2} ight ) ight ]^{1/4}$$

$$Rightarrow R_{Max}=left [frac{P_tGsigma {A_e}^2}{4pi lambda^2 S_{min}} ight ]^{1/4}:::::Equation:9$$

Equation 9 represents the modified form of Radar range equation. By using the above equation, we can find the maximum range of the target.

We will get the following relation between effective aperture, $A_e$ and the Gain of directional Antenna, $G$ from Equation 8.

$$A_e=frac{Glambda^2}{4pi}:::::Equation:10$$

Substitute, Equation 10 in Equation 7.

$$R_{Max}=left [frac{P_tGsigma}{left (4pi ight )^2 S_{min}}(frac{Glambda^2}{4pi}) ight ]^{1/4}$$

$$Rightarrow R_{Max}=left [frac{P_tG^2 lambda^2 sigma}{left (4pi ight )^2 S_{min}} ight ]^{1/4}:::::Equation:11$$

Equation 11 represents another modified form of Radar range equation. By using the above equation, we can find the maximum range of the target.

Note − Based on the given data, we can find the maximum range of the target by using one of these three equations namely

Equation 7

Equation 9

Equation 11

Example Problems

In previous section, we got the standard and modified forms of the Radar range equation. Now, let us solve a few problems by using those equations.

Problem 1

Calculate the maximum range of Radar for the following specifications −

Peak power transmitted by the Radar, $P_t=250KW$

Gain of transmitting Antenna, $G=4000$

Effective aperture of the receiving Antenna, $A_e=4:m^2$

Radar cross section of the target, $sigma=25:m^2$

Power of minimum detectable signal, $S_{min}=10^{-12}W$

Solution

We can use the following standard form of Radar range equation in order to calculate the maximum range of Radar for given specifications.

$$R_{Max}=left [frac{P_tG sigma A_e}{left (4pi ight )^2 S_{min}} ight ]^{1/4}$$

Substitute all the given parameters in above equation.

$$R_{Max}=left [frac{ left ( 250 imes 10^3 ight )left ( 4000 ight )left ( 25 ight )left ( 4 ight )}{left ( 4pi ight )^2 left ( 10^{-12} ight )} ight ]^{1/4}$$

$$Rightarrow R_{Max}=158:KM$$

Therefore, the maximum range of Radar for given specifications is $158:KM$.

Problem 2

Calculate the maximum range of Radar for the following specifications.

Operating frequency, $f=10GHZ$

Peak power transmitted by the Radar, $P_t=400KW$

Effective aperture of the receiving Antenna, $A_e=5:m^2$

Radar cross section of the target, $sigma=30:m^2$

Power of minimum detectable signal, $S_{min}=10^{-10}W$

Solution

We know the following formula for operating wavelength, $lambda$ in terms of operating frequency, f.

$$lambda =frac{C}{f}$$

Substitute, $C=3 imes 10^8m/sec$ and $f=10GHZ$ in above equation.

$$lambda =frac{3 imes 10^8}{10 imes 10^9}$$

$$Rightarrow lambda=0.03m$$

So, the operating wavelength,$lambda$ is equal to $0.03m$, when the operating frequency, $f$ is $10GHZ$.

We can use the following modified form of Radar range equation in order to calculate the maximum range of Radar for given specifications.

$$R_{Max}=left [frac{P_t sigma {A_e}^2}{4pi lambda^2 S_{min}} ight ]^{1/4}$$

Substitute, the given parameters in the above equation.

$$R_{Max}=left [ frac{left ( 400 imes 10^3 ight )left ( 30 ight )left ( 5^2 ight )}{4pileft ( 0.003 ight )^2left ( 10 ight )^{-10}} ight ]^{1/4}$$

$$Rightarrow R_{Max}=128KM$$

Therefore, the maximum range of Radar for given specifications is $128:KM$.

Radar Systems - Performance Factors

The factors, which affect the performance of Radar are known as Radar performance factors. In this chapter, let us discuss about those factors. We know that the following standard form of Radar range equation, which is useful for calculating the maximum range of Radar for given specifications.

$$R_{Max}=left [frac{P_tGsigma A_e}{left (4pi ight )^2 S_{min}} ight ]^{1/4}$$

Where,

$P_t$ is the peak power transmitted by the Radar

$G$ is the gain of transmitting Antenna

$sigma$ is the Radar cross section of the target

$A_e$ is the effective aperture of the receiving Antenna

$S_{min}$ is the power of minimum detectable signal

From the above equation, we can conclude that the following conditions should be considered in order to get the range of the Radar as maximum.

Peak power transmitted by the Radar $P_t$ should be high.

Gain of the transmitting Antenna $G$ should be high.

Radar cross section of the target $sigma$ should be high.

Effective aperture of the receiving Antenna $A_e$ should be high.

Power of minimum detectable signal $S_{min}$ should be low.

It is difficult to predict the range of the target from the standard form of the Radar range equation. This means, the degree of accuracy that is provided by the Radar range equation about the range of the target is less. Because, the parameters pke Radar cross section of the target, $sigma$ and minimum detectable signal, $S_{min}$ are statistical in nature.

Minimum Detectable Signal

If the echo signal has minimum power, detecting that signal by the Radar is known as minimum detectable signal. This means, Radar cannot detect the echo signal if that signal is having less power than that of minimum power.

In general, Radar receives the echo signal in addition with noise. If the threshold value is used for detecting the presence of the target from the received signal, then that detection is called threshold detection.

We have to select proper threshold value based on the strength of the signal to be detected.

A high threshold value should be chosen when the strength of the signal to be detected is high so that it will epminate the unwanted noise signal present in it.

Similarly, a low threshold value should be chosen when the strength of the signal to be detected is low.

The following figure illustrates this concept −

A typical waveform of the Radar receiver is shown in the above figure. The x-axis and y-axis represent time and voltage respectively. The rms value of noise and threshold value are indicated with dotted pnes in the above figure.

We have considered three points, A, B & C in above figure for identifying the vapd detections and missing detections.

The value of the signal at point A is greater than threshold value. Hence, it is a vapd detection.

The value of the signal at point B is equal to threshold value. Hence, it is a vapd detection.

Even though the value of the signal at point C is closer to threshold value, it is a missing detection. Because, the value of the signal at point C is less than threshold value.

So, the points, A & B are vapd detections. Whereas, the point C is a missing detection.

Receiver Noise

If the receiver generates a noise component into the signal, which is received at the receiver, then that kind of noise is known as receiver noise. The receiver noise is an unwanted component; we should try to epminate it with some precautions.

However, there exists one kind of noise that is known as the thermal noise. It occurs due to thermal motion of conduction electrons. Mathematically, we can write thermal noise power, $N_i$ produced at receiver as −

$$N_i=KT_oB_n$$

Where,

$K$ is the Boltzmann s constant and it is equal to $1.38 imes 10^{-23}J/deg$

$T_o$ is the absolute temperature and it is equal to $290^0K$

$B_n$ is the receiver band width

Figure of Merit

The Figure of Merit, F is nothing but the ratio of input SNR, $(SNR)_i$ and output SNR, $(SNR)_o$. Mathematically, it can be represented as −

$$F=frac{(SNR)_i}{(SNR)_o}$$

$$Rightarrow F=frac{S_i/N_i}{S_o/N_o}$$

$$Rightarrow F=frac{N_oS_i}{N_iS_o}$$

$$Rightarrow S_i=frac{FN_iS_o}{N_o}$$

Substitute, $N_i=KT_oB_n$ in above equation.

$$Rightarrow S_i=FKT_oB_nleft ( frac{S_o}{N_o} ight )$$

Input signal power will be having minimum value, when output SNR is having minimum value.

$$Rightarrow S_{min}=FKT_oB_nleft ( frac{S_o}{N_o} ight )_{min}$$

Substitute, the above $S_{min}$ in the following standard form of Radar range equation.

$$R_{Max}=left [frac{P_tGsigma A_e}{left (4pi ight )^2 S_{min}} ight ]^{1/4}$$

$$Rightarrow R_{Max}=left [frac{P_tGsigma A_e}{left (4pi ight )^2 FKT_oB_nleft ( frac{S_o}{N_o} ight )_{min}} ight ]^{1/4}$$

From the above equation, we can conclude that the following conditions should be considered in order to get the range of the Radar as maximum.

Peak power transmitted by the Radar, $P_t$ should be high.

Gain of the transmitting Antenna $G$ should be high.

Radar cross section of the target $sigma$ should be high.

Effective aperture of the receiving Antenna $A_e$ should be high.

Figure of Merit F should be low.

Receiver bandwidth $B_n$ should be low.

Radar Systems - Types of Radars

In this chapter, we will discuss in brief the different types of Radar. This chapter provides the information briefly about the types of Radars. Radars can be classified into the following two types based on the type of signal with which Radar can be operated.

Pulse Radar

Continuous Wave Radar

Now, let us discuss about these two types of Radars one by one.

Pulse Radar

The Radar, which operates with pulse signal is called the Pulse Radar. Pulse Radars can be classified into the following two types based on the type of the target it detects.

Basic Pulse Radar

Moving Target Indication Radar

Let us now discuss the two Radars briefly.

Basic Pulse Radar

The Radar, which operates with pulse signal for detecting stationary targets, is called the Basic Pulse Radar or simply, Pulse Radar. It uses single Antenna for both transmitting and receiving signals with the help of Duplexer.

Antenna will transmit a pulse signal at every clock pulse. The duration between the two clock pulses should be chosen in such a way that the echo signal corresponding to the present clock pulse should be received before the next clock pulse.

Moving Target Indication Radar

The Radar, which operates with pulse signal for detecting non-stationary targets, is called Moving Target Indication Radar or simply, MTI Radar. It uses single Antenna for both transmission and reception of signals with the help of Duplexer.

MTI Radar uses the principle of Doppler effect for distinguishing the non-stationary targets from stationary objects.

Continuous Wave Radar

The Radar, which operates with continuous signal or wave is called Continuous Wave Radar. They use Doppler Effect for detecting non-stationary targets. Continuous Wave Radars can be classified into the following two types.

Unmodulated Continuous Wave Radar

Frequency Modulated Continuous Wave Radar

Now, let us discuss the two Radars briefly.

Unmodulated Continuous Wave Radar

The Radar, which operates with continuous signal (wave) for detecting non-stationary targets is called Unmodulated Continuous Wave Radar or simply, CW Radar. It is also called CW Doppler Radar.

This Radar requires two Antennas. Of these two antennas, one Antenna is used for transmitting the signal and the other Antenna is used for receiving the signal. It measures only the speed of the target but not the distance of the target from the Radar.

Frequency Modulated Continuous Wave Radar

If CW Doppler Radar uses the Frequency Modulation, then that Radar is called the Frequency Modulated Continuous Wave (FMCW) Radar or FMCW Doppler Radar. It is also called Continuous Wave Frequency Modulated Radar or CWFM Radar.

This Radar requires two Antennas. Among which, one Antenna is used for transmitting the signal and the other Antenna is used for receiving the signal. It measures not only the speed of the target but also the distance of the target from the Radar.

In our subsequent chapters, we will discuss the operations of all these Radars in detail.

Radar Systems - Pulse Radar

The Radar, which operates with pulse signal for detecting stationary targets is called Basic Pulse Radar or simply, Pulse Radar. In this chapter, let us discuss the working of Pulse Radar.

Block Diagram of Pulse Radar

Pulse Radar uses single Antenna for both transmitting and receiving of signals with the help of Duplexer. Following is the block diagram of Pulse Radar −

Let us now see the function of each block of Pulse Radar −

Pulse Modulator − It produces a pulse-modulated signal and it is appped to the Transmitter.

Transmitter − It transmits the pulse-modulated signal, which is a train of repetitive pulses.

Duplexer − It is a microwave switch, which connects the Antenna to both transmitter section and receiver section alternately. Antenna transmits the pulse-modulated signal, when the duplexer connects the Antenna to the transmitter. Similarly, the signal, which is received by Antenna will be given to Low Noise RF Amppfier, when the duplexer connects the Antenna to Low Noise RF Amppfier.

Low Noise RF Amppfier − It amppfies the weak RF signal, which is received by Antenna. The output of this amppfier is connected to Mixer.

Local Oscillator − It produces a signal having stable frequency. The output of Local Oscillator is connected to Mixer.

Mixer − We know that Mixer can produce both sum and difference of the frequencies that are appped to it. Among which, the difference of the frequencies will be of Intermediate Frequency (IF) type.

IF Amppfier − IF amppfier amppfies the Intermediate Frequency (IF) signal. The IF amppfier shown in the figure allows only the Intermediate Frequency, which is obtained from Mixer and amppfies it. It improves the Signal to Noise Ratio at output.

Detector − It demodulates the signal, which is obtained at the output of the IF Amppfier.

Video Amppfier − As the name suggests, it amppfies the video signal, which is obtained at the output of detector.

Display − In general, it displays the amppfied video signal on CRT screen.

In this chapter, we discussed how the Pulse Radar works and how it is useful for detecting stationary targets. In our subsequent chapters, we will discuss the Radars, which are useful for detecting non-stationary targets.

Radar Systems - Doppler Effect

In this chapter, we will learn about the Doppler Effect in Radar Systems.

If the target is not stationary, then there will be a change in the frequency of the signal that is transmitted from the Radar and that is received by the Radar. This effect is known as the Doppler effect.

According to the Doppler effect, we will get the following two possible cases −

The frequency of the received signal will increase, when the target moves towards the direction of the Radar.

The frequency of the received signal will decrease, when the target moves away from the Radar.

Now, let us derive the formula for Doppler frequency.

Derivation of Doppler Frequency

The distance between Radar and target is nothing but the Range of the target or simply range, R. Therefore, the total distance between the Radar and target in a two-way communication path will be 2R, since Radar transmits a signal to the target and accordingly the target sends an echo signal to the Radar.

If $lambda$ is one wave length, then the number of wave lengths N that are present in a two-way communication path between the Radar and target will be equal to $2R/lambda$.

We know that one wave length $lambda$ corresponds to an angular excursion of $2pi$ radians. So, the total angle of excursion made by the electromagnetic wave during the two-way communication path between the Radar and target will be equal to $4pi R/lambda$ radians.

Following is the mathematical formula for angular frequency, $omega$ −

$$omega=2pi f:::::Equation:1$$

Following equation shows the mathematical relationship between the angular frequency $omega$ and phase angle $phi$ −

$$omega=frac{dphi }{dt}:::::Equation:2$$

Equate the right hand side terms of Equation 1 and Equation 2 since the left hand side terms of those two equations are same.

$$2pi f=frac{dphi }{dt}$$

$$Rightarrow f =frac{1}{2pi}frac{dphi }{dt}:::::Equation:3$$

Substitute,$f=f_d$ and $phi=4pi R/lambda$ in Equation 3.

$$f_d =frac{1}{2pi}frac{d}{dt}left ( frac{4pi R}{lambda} ight )$$

$$Rightarrow f_d =frac{1}{2pi}frac{4pi}{lambda}frac{dR}{dt}$$

$$Rightarrow f_d =frac{2V_r}{lambda}:::::Equation:4$$

Where,

$f_d$ is the Doppler frequency

$V_r$ is the relative velocity

We can find the value of Doppler frequency $f_d$ by substituting the values of $V_r$ and $lambda$ in Equation 4.

Substitute, $lambda=C/f$ in Equation 4.

$$f_d =frac{2V_r}{C/f}$$

$$Rightarrow f_d =frac{2V_rf}{C}:::::Equation:5$$

Where,

$f$ is the frequency of transmitted signal

$C$ is the speed of pght and it is equal to $3 imes 10^8m/sec$

We can find the value of Doppler frequency, $f_d$ by substituting the values of $V_r,f$ and $C$ in Equation 5.

Note − Both Equation 4 and Equation 5 show the formulae of Doppler frequency, $f_d$. We can use either Equation 4 or Equation 5 for finding Doppler frequency, $f_d$ based on the given data.

Example Problem

If the Radar operates at a frequency of $5GHZ$, then find the Doppler frequency of an aircraft moving with a speed of 100KMph.

Solution

Given,

The frequency of transmitted signal, $f=5GHZ$

Speed of aircraft (target), $V_r=100KMph$

$$Rightarrow V_r=frac{100 imes 10^3}{3600}m/sec$$

$$Rightarrow V_r=27.78m/sec$$

We have converted the given speed of aircraft (target), which is present in KMph into its equivalent m/sec.

We know that, the speed of the pght, $C=3 imes 10^8m/sec$

Now, following is the formula for Doppler frequency −

$$f_d=frac{2Vrf}{C}$$

Substitute the values of 𝑉𝑟, $V_r,f$ and $C$ in the above equation.

$$Rightarrow f_d=frac{2left ( 27.78 ight )left ( 5 imes 10^9 ight )}{3 imes 10^8}$$

$$Rightarrow f_d=926HZ$$

Therefore, the value of Doppler frequency, $f_d$ is $926HZ$ for the given specifications.

Radar Systems - CW Radar

basic Radar uses the same Antenna for both transmission and reception of signals. We can use this type of Radar, when the target is stationary, i.e., not moving and / or when that Radar can be operated with pulse signal.

The Radar, which operates with continuous signal (wave) for detecting non-stationary targets, is called Continuous Wave Radar or simply CW Radar. This Radar requires two Antennas. Among which, one Antenna is used for transmitting the signal and the other Antenna is used for receiving the signal.

Block Diagram of CW Radar

We know that CW Doppler Radar contains two Antennas − transmitting Antenna and receiving Antenna. Following figure shows the block diagram of CW Radar −

The block diagram of CW Doppler Radar contains a set of blocks and the function of each block is mentioned below.

CW Transmitter − It produces an analog signal having a frequency of $f_o$. The output of CW Transmitter is connected to both transmitting Antenna and Mixer-I.

Local Oscillator − It produces a signal having a frequency of $f_l$. The output of Local Oscillator is connected to Mixer-I.

Mixer-I − Mixer can produce both sum and difference of the frequencies that are appped to it. The signals having frequencies of $f_o$ and $f_l$ are appped to Mixer-I. So, the Mixer-I will produce the output having frequencies $f_o+f_l$ or $f_o−f_l$.

Side Band Filter − As the name suggests, side band filter allows a particular side band frequencies − either upper side band frequencies or lower side band frequencies. The side band filter shown in the above figure produces only upper side band frequency, i.e., $f_o+f_l$.

Mixer-II − Mixer can produce both sum and difference of the frequencies that are appped to it. The signals having frequencies of $f_o+f_l$ and $f_opm f_d$ are appped to Mixer-II. So, the Mixer-II will produce the output having frequencies of 2$f_o+f_lpm f_d$ or $f_lpm f_d$.

IF Amppfier − IF amppfier amppfies the Intermediate Frequency (IF) signal. The IF amppfier shown in the figure allows only the Intermediate Frequency, $f_lpm f_d$ and amppfies it.

Detector − It detects the signal, which is having Doppler frequency, $f_d$.

Doppler Amppfier − As the name suggests, Doppler amppfier amppfies the signal, which is having Doppler frequency, $f_d$.

Indicator − It indicates the information related relative velocity and whether the target is inbound or outbound.

CW Doppler Radars give accurate measurement of relative velocities. Hence, these are used mostly, where the information of velocity is more important than the actual range.

Radar Systems - FMCW Radar

If CW Doppler Radar uses the Frequency Modulation, then that Radar is called FMCW Doppler Radar or simply, FMCW Radar. It is also called Continuous Wave Frequency Modulated Radar or CWFM Radar. It measures not only the speed of the target but also the distance of the target from the Radar.

Block Diagram of FMCW Radar

FMCW Radar is mostly used as Radar Altimeter in order to measure the exact height while landing the aircraft. The following figure shows the block diagram of FMCW Radar −

FMCW Radar contains two Antennas − transmitting Antenna and receiving Antenna as shown in the figure. The transmitting Antenna transmits the signal and the receiving Antenna receives the echo signal.

The block diagram of the FMCW Radar looks similar to the block diagram of CW Radar. It contains few modified blocks and some other blocks in addition to the blocks that are present in the block diagram of CW Radar. The function of each block of FMCW Radar is mentioned below.

FM Modulator − It produces a Frequency Modulated (FM) signal having variable frequency, $f_oleft (t ight )$ and it is appped to the FM transmitter.

FM Transmitter − It transmits the FM signal with the help of transmitting Antenna. The output of FM Transmitter is also connected to Mixer-I.

Local Oscillator − In general, Local Oscillator is used to produce an RF signal. But, here it is used to produce a signal having an Intermediate Frequency, $f_{IF}$. The output of Local Oscillator is connected to both Mixer-I and Balanced Detector.

Mixer-I − Mixer can produce both sum and difference of the frequencies that are appped to it. The signals having frequencies of $f_oleft (t ight )$ and $f_{IF}$ are appped to Mixer-I. So, the Mixer-I will produce the output having frequency either $f_oleft (t ight )+f_{IF}$ or $f_oleft (t ight )-f_{IF}$.

Side Band Filter − It allows only one side band frequencies, i.e., either upper side band frequencies or lower side band frequencies. The side band filter shown in the figure produces only lower side band frequency. i.e., $f_oleft (t ight )-f_{IF}$.

Mixer-II − Mixer can produce both sum and difference of the frequencies that are appped to it. The signals having frequencies of $f_oleft (t ight )-f_{IF}$ and $f_oleft (t-T ight )$ are appped to Mixer-II. So, the Mixer-II will produce the output having frequency either $f_oleft (t-T ight )+f_oleft (t ight )-f_{IF}$ or $f_oleft (t-T ight )-f_oleft (t ight )+f_{IF}$.

IF Amppfier − IF amppfier amppfies the Intermediate Frequency (IF) signal. The IF amppfier shown in the figure amppfies the signal having frequency of $f_oleft (t-T ight )-f_oleft (t ight )+f_{IF}$. This amppfied signal is appped as an input to the Balanced detector.

Balanced Detector − It is used to produce the output signal having frequency of $f_oleft (t-T ight )-f_oleft (t ight )$ from the appped two input signals, which are having frequencies of $f_oleft (t-T ight )-f_oleft (t ight )+f_{IF}$ and $f_{IF}$. The output of Balanced detector is appped as an input to Low Frequency Amppfier.

Low Frequency Amppfier − It amppfies the output of Balanced detector to the required level. The output of Low Frequency Amppfier is appped to both switched frequency counter and average frequency counter.

Switched Frequency Counter − It is useful for getting the value of Doppler velocity.

Average Frequency Counter − It is useful for getting the value of Range.

Radar Systems - MTI Radar

If the Radar is used for detecting the movable target, then the Radar should receive only the echo signal due to that movable target. This echo signal is the desired one. However, in practical apppcations, Radar receives the echo signals due to stationary objects in addition to the echo signal due to that movable target.

The echo signals due to stationary objects (places) such as land and sea are called clutters because these are unwanted signals. Therefore, we have to choose the Radar in such a way that it considers only the echo signal due to movable target but not the clutters.

For this purpose, Radar uses the principle of Doppler Effect for distinguishing the non-stationary targets from stationary objects. This type of Radar is called Moving Target Indicator Radar or simply, MTI Radar.

According to Doppler effect, the frequency of the received signal will increase if the target is moving towards the direction of Radar. Similarly, the frequency of the received signal will decrease if the target is moving away from the Radar.

Types of MTI Radars

We can classify the MTI Radars into the following two types based on the type of transmitter that has been used.

MTI Radar with Power Amppfier Transmitter

MTI Radar with Power Oscillator Transmitter

Now, let us discuss about these two MTI Radars one by one.

MTI Radar with Power Amppfier Transmitter

MTI Radar uses single Antenna for both transmission and reception of signals with the help of Duplexer. The block diagram of MTI Radar with power amppfier transmitter is shown in the following figure.

The function of each block of MTI Radar with power amppfier transmitter is mentioned below.

Pulse Modulator − It produces a pulse modulated signal and it is appped to Power Amppfier.

Power Amppfier − It amppfies the power levels of the pulse modulated signal.

Local Oscillator − It produces a signal having stable frequency $f_l$. Hence, it is also called stable Local Oscillator. The output of Local Oscillator is appped to both Mixer-I and Mixer-II.

Coherent Oscillator − It produces a signal having an Intermediate Frequency, $f_c$. This signal is used as the reference signal. The output of Coherent Oscillator is appped to both Mixer-I and Phase Detector.

Mixer-I − Mixer can produce either sum or difference of the frequencies that are appped to it. The signals having frequencies of $f_l$ and $f_c$ are appped to Mixer-I. Here, the Mixer-I is used for producing the output, which is having the frequency $f_l+f_c$.

Duplexer − It is a microwave switch, which connects the Antenna to either the transmitter section or the receiver section based on the requirement. Antenna transmits the signal having frequency $f_l+f_c$ when the duplexer connects the Antenna to power amppfier. Similarly, Antenna receives the signal having frequency of $f_l+f_cpm f_d$ when the duplexer connects the Antenna to Mixer-II.

Mixer-II − Mixer can produce either sum or difference of the frequencies that are appped to it. The signals having frequencies $f_l+f_cpm f_d$ and $f_l$ are appped to Mixer-II. Here, the Mixer-II is used for producing the output, which is having the frequency $f_cpm f_d$.

IF Amppfier − IF amppfier amppfies the Intermediate Frequency (IF) signal. The IF amppfier shown in the figure amppfies the signal having frequency $f_c+f_d$. This amppfied signal is appped as an input to Phase detector.

Phase Detector − It is used to produce the output signal having frequency $f_d$ from the appped two input signals, which are having the frequencies of $f_c+f_d$ and $f_c$. The output of phase detector can be connected to Delay pne canceller.

MTI Radar with Power Oscillator Transmitter

The block diagram of MTI Radar with power oscillator transmitter looks similar to the block diagram of MTI Radar with power amppfier transmitter. The blocks corresponding to the receiver section will be same in both the block diagrams. Whereas, the blocks corresponding to the transmitter section may differ in both the block diagrams.

The block diagram of MTI Radar with power oscillator transmitter is shown in the following figure.

As shown in the figure, MTI Radar uses the single Antenna for both transmission and reception of signals with the help of Duplexer. The operation of MTI Radar with power oscillator transmitter is mentioned below.

The output of Magnetron Oscillator and the output of Local Oscillator are appped to Mixer-I. This will further produce an IF signal, the phase of which is directly related to the phase of the transmitted signal.

The output of Mixer-I is appped to the Coherent Oscillator. Therefore, the phase of Coherent Oscillator output will be locked to the phase of IF signal. This means, the phase of Coherent Oscillator output will also directly relate to the phase of the transmitted signal.

So, the output of Coherent Oscillator can be used as reference signal for comparing the received echo signal with the corresponding transmitted signal using phase detector.

The above tasks will be repeated for every newly transmitted signal.

Radar Systems - Delay Line Cancellers

In this chapter, we will learn about Delay Line Cancellers in Radar Systems. As the name suggests, delay pne introduces a certain amount of delay. So, the delay pne is mainly used in Delay pne canceller in order to introduce a delay of pulse repetition time.

Delay pne canceller is a filter, which epminates the DC components of echo signals received from stationary targets. This means, it allows the AC components of echo signals received from non-stationary targets, i.e., moving targets.

Types of Delay Line Cancellers

Delay pne cancellers can be classified into the following two types based on the number of delay pnes that are present in it.

Single Delay Line Canceller

Double Delay Line Canceller

In our subsequent sections, we will discuss more about these two Delay pne cancellers.

Single Delay Line Canceller

The combination of a delay pne and a subtractor is known as Delay pne canceller. It is also called single Delay pne canceller. The block diagram of MTI receiver with single Delay pne canceller is shown in the figure below.

We can write the mathematical equation of the received echo signal after the Doppler effect as −

$$V_1=Asinleft [ 2pi f_dt-phi_0 ight ]:::::Equation:1$$

Where,

A is the ampptude of video signal

$f_d$ is the Doppler frequency

$phi_o$ is the phase shift and it is equal to $4pi f_tR_o/C$

We will get the output of Delay pne canceller, by replacing $t$ by $t-T_P$ in Equation 1.

$$V_2=Asinleft [ 2pi f_dleft ( t-T_P ight )-phi_0 ight ]:::::Equation:2$$

Where,

$T_P$ is the pulse repetition time

We will get the subtractor output by subtracting Equation 2 from Equation 1.

$$V_1-V_2=Asinleft [ 2pi f_dt-phi_0 ight ]-Asinleft [ 2pi f_dleft ( t-T_P ight )-phi_0 ight ]$$

$$Rightarrow V_1-V_2=2Asinleft [ frac{ 2pi f_dt-phi_0-left [ 2pi f_dleft ( t-T_P ight )-phi_0 ight ]}{2} ight ]cosleft [ frac{ 2pi f_dt-phi_o+2pi f_dleft ( t-T_P ight )-phi_0 }{2} ight ]$$

$$V_1-V_2=2Asinleft [ frac{2pi f_dT_P}{2} ight ]cosleft [ frac{2pi f_dleft ( 2t-T_P ight )-2phi_0}{2} ight ]$$

$$Rightarrow V_1-V_2=2Asinleft [ pi f_dT_p ight ]cosleft [ 2pi f_dleft ( t-frac{T_P}{2} ight )-phi_0 ight ]:::::Equation:3$$

The output of subtractor is appped as input to Full Wave Rectifier. Therefore, the output of Full Wave Rectifier looks pke as shown in the following figure. It is nothing but the frequency response of the single delay pne canceller.

From Equation 3, we can observe that the frequency response of the single delay pne canceller becomes zero, when $pi f_dT_P$ is equal to integer multiples of $pi$ This means, $pi f_dT_P$ is equal to $npi$ Mathematically, it can be written as

$$pi f_dT_P=npi$$

$$Rightarrow f_dT_P=n$$

$$Rightarrow f_d=frac{n}{T_P}:::::Equation:4$$

From Equation 4, we can conclude that the frequency response of the single delay pne canceller becomes zero, when Doppler frequency $f_d$ is equal to integer multiples of reciprocal of pulse repetition time $T_P$.

We know the following relation between the pulse repetition time and pulse repetition frequency.

$$f_d=frac{1}{T_P}$$

$$Rightarrow frac{1}{T_P}=f_P:::::Equation:5$$

We will get the following equation, by substituting Equation 5 in Equation 4.

$$Rightarrow f_d=nf_P:::::Equation:6$$

From Equation 6, we can conclude that the frequency response of the single delay pne canceller becomes zero, when Doppler frequency, $f_d$ is equal to integer multiples of pulse repetition frequency $f_P$.

Bpnd Speeds

From what we learnt so far, single Delay pne canceller epminates the DC components of echo signals received from stationary targets, when $n$ is equal to zero. In addition to that, it also epminates the AC components of echo signals received from non-stationary targets, when the Doppler frequency $f_d$ is equal to integer (other than zero) multiples of pulse repetition frequency $f_P$.

So, the relative velocities for which the frequency response of the single delay pne canceller becomes zero are called bpnd speeds. Mathematically, we can write the expression for bpnd speed $v_n$ as −

$$v_n=frac{nlambda}{2T_P}:::::Equation:7$$

$$Rightarrow v_n=frac{nlambda f_P}{2}:::::Equation:8$$

Where,

$n$ is an integer and it is equal to 1, 2, 3 and so on

$lambda$ is the operating wavelength

Example Problem

An MTI Radar operates at a frequency of $6GHZ$ with a pulse repetition frequency of $1KHZ$. Find the first, second and third bpnd speeds of this Radar.

Solution

Given,

The operating frequency of MTI Radar, $f=6GHZ$

Pulse repetition frequency, $f_P=1KHZ$.

Following is the formula for operating wavelength $lambda$ in terms of operating frequency, f.

$$lambda=frac{C}{f}$$

Substitute, $C=3 imes10^8m/sec$ and $f=6GHZ$ in the above equation.

$$lambda=frac{3 imes10^8}{6 imes10^9}$$

$$Rightarrow lambda=0.05m$$

So, the operating wavelength $lambda$ is equal to $0.05m$, when the operating frequency f is $6GHZ$.

We know the following formula for bpnd speed.

$$v_n=frac{nlambda f_p}{2}$$

By substituting, $n$=1,2 & 3 in the above equation, we will get the following equations for first, second & third bpnd speeds respectively.

$$v_1=frac{1 imes lambda f_p}{2}=frac{lambda f_p}{2}$$

$$v_2=frac{2 imes lambda f_p}{2}=2left ( frac{lambda f_p}{2} ight )=2v_1$$

$$v_3=frac{3 imes lambda f_p}{2}=3left ( frac{lambda f_p}{2} ight )=3v_1$$

Substitute the values of $lambda$ and $f_P$ in the equation of first bpnd speed.

$$v_1=frac{0.05 imes 10^3}{2}$$

$$Rightarrow v_1=25m/sec$$

Therefore, the first bpnd speed $v_1$ is equal to $25m/sec$ for the given specifications.

We will get the values of second & third bpnd speeds as $50m/sec$& $75m/sec$ respectively by substituting the value of 𝑣1 in the equations of second & third bpnd speeds.

Double Delay Line Canceller

We know that a single delay pne canceller consists of a delay pne and a subtractor. If two such delay pne cancellers are cascaded together, then that combination is called Double delay pne canceller. The block diagram of Double delay pne canceller is shown in the following figure.

Let $pleft ( t ight )$ and $qleft ( t ight )$ be the input and output of the first delay pne canceller. We will get the following mathematical relation from first delay pne canceller.

$$qleft ( t ight )=pleft ( t ight )-pleft ( t-T_P ight ):::::Equation:9$$

The output of the first delay pne canceller is appped as an input to the second delay pne canceller. Hence, $qleft ( t ight )$ will be the input of the second delay pne canceller. Let $rleft ( t ight )$ be the output of the second delay pne canceller. We will get the following mathematical relation from the second delay pne canceller.

$$rleft ( t ight )=qleft ( t ight )-qleft ( t-T_P ight ):::::Equation:10$$

Replace $t$ by $t-T_P$ in Equation 9.

$$qleft ( t-T_P ight )=pleft ( t-T_P ight )-pleft ( t-T_P-T_P ight )$$

$$qleft ( t-T_P ight )=pleft ( t-T_P ight )-pleft ( t-2T_P ight ):::::Equation:11$$

Substitute, Equation 9 and Equation 11 in Equation 10.

$$rleft ( t ight )=pleft ( t ight )-pleft ( t-T_P ight )-left [ pleft ( t-T_P ight )-pleft ( t-2T_P ight ) ight ]$$

$$Rightarrow rleft ( t ight )=pleft ( t ight )-2pleft ( t-T_P ight )+pleft ( t-2T_P ight ):::::Equation:12$$

The advantage of double delay pne canceller is that it rejects the clutter broadly. The output of two delay pne cancellers, which are cascaded, will be equal to the square of the output of single delay pne canceller.

So, the magnitude of output of double delay pne canceller, which is present at MTI Radar receiver will be equal to $4A^2left ( sinleft [ pi f_dT_P ight ] ight )^2$.

The frequency response characteristics of both double delay pne canceller and the cascaded combination of two delay pne cancellers are the same. The advantage of time domain delay pne canceller is that it can be operated for all frequency ranges.

Radar Systems - Tracking Radar

The Radar, which is used to track the path of one or more targets is known as Tracking Radar. In general, it performs the following functions before it starts the tracking activity.

Target detection

Range of the target

Finding elevation and azimuth angles

Finding Doppler frequency shift

So, Tracking Radar tracks the target by tracking one of the three parameters — range, angle, Doppler frequency shift. Most of the Tracking Radars use the principle of tracking in angle. Now, let us discuss what angular tracking is.

Angular Tracking

The pencil beams of Radar Antenna perform tracking in angle. The axis of Radar Antenna is considered as the reference direction. If the direction of the target and reference direction is not same, then there will be angular error, which is nothing but the difference between the two directions.

If the angular error signal is appped to a servo control system, then it will move the axis of the Radar Antenna towards the direction of target. Both the axis of Radar Antenna and the direction of target will coincide when the angular error is zero. There exists a feedback mechanism in the Tracking Radar, which works until the angular error becomes zero.

Following are the two techniques, which are used in angular tracking.

Sequential Lobing

Conical Scanning

Now, let us discuss about these two techniques one by one.

Sequential Lobing

If the Antenna beams are switched between two patterns alternately for tracking the target, then it is called sequential lobing. It is also called sequential switching and lobe switching. This technique is used to find the angular error in one coordinate. It gives the details of both magnitude and direction of angular error.

Following figure shows an example of sequential lobing in polar coordinates.

As shown in the figure, Antenna beams switch between Position 1 and Position 2 alternately. Angular error θ is indicated in the above figure. Sequential lobing gives the position of the target with high accuracy. This is the main advantage of sequential lobing.

Conical Scanning

If the Antenna beam continuously rotates for tracking a target, then it is called conical scanning. Conical scan modulation is used to find the position of the target. Following figure shows an example of conical scanning.

Squint angle is the angle between beam axis and rotation axis and it is shown in the above figure. The echo signal obtained from the target gets modulated at a frequency equal to the frequency at which the Antenna beam rotates.

The angle between the direction of the target and the rotation axis determines the ampptude of the modulated signal. So, the conical scan modulation has to be extracted from the echo signal and then it is to be appped to servo control system, which moves the Antenna beam axis towards the direction of the target.

Radar Systems - Antenna Parameters

An Antenna or Aerial is a transducer, which converts electrical power into electromagnetic waves and vice versa.

An Antenna has the following parameters −

Directivity

Aperture Efficiency

Antenna Efficiency

Gain

Now, let us discuss these parameters in detail −

Directivity

According to the standard definition, “The ratio of maximum radiation intensity of the subject Antenna to the radiation intensity of an isotropic or reference Antenna, radiating the same total power is called the Directivity.”

Though an Antenna radiates power, the direction in which it radiates matters is of much significance. The Antenna under study is termed as subject Antenna. Its radiation intensity is focused in a particular direction, while it is transmitting or receiving. Hence, the Antenna is said to have its directivity in that particular direction.

The ratio of radiation intensity in a given direction from an Antenna to the radiation intensity averaged over all directions, is termed as Directivity.

If that particular direction is not specified, then the direction in which maximum intensity is observed, can be taken as the directivity of that Antenna.

The directivity of a non-isotropic Antenna is equal to the ratio of the radiation intensity in a given direction to the radiation intensity of the isotropic source.

Mathematically, we can write the expression for Directivity as −

$$Directivity=frac{U_{Max}left ( heta,phi ight )}{U_0}$$

Where,

$U_{Max}left ( heta,phi ight )$ is the maximum radiation intensity of subject Antenna

$U_0$ is the radiation intensity of an isotropic Antenna.

Aperture Efficiency

According to the standard definition, “Aperture efficiency of an Antenna is the ratio of the effective radiating area (or effective area) to the physical area of the aperture.”

An Antenna radiates power through an aperture. This radiation should be effective with minimum losses. The physical area of the aperture should also be taken into consideration, as the effectiveness of the radiation depends upon the area of the aperture, physically on the Antenna.

Mathematically, we can write the expression for Aperture efficiency $epsilon_A$ as

$$epsilon _A=frac{A_{eff}}{A_p}$$

Where,

$A_{eff}$ is the effective area

$A_P$ is the physical area

Antenna Efficiency

According to the standard definition, “Antenna Efficiency is the ratio of the radiated power of the Antenna to the input power accepted by the Antenna.”

Any Antenna is designed to radiate power with minimum losses, for a given input. The efficiency of an Antenna explains how much an Antenna is able to depver its output effectively with minimum losses in the transmission pne. It is also called Radiation Efficiency Factor of the Antenna.

Mathematically, we can write the expression for Antenna efficiency ?? as −

$$eta _e=frac{P_{Rad}}{P_{in}}$$

Where,

$P_{Rad}$ is the amount of power radiated

$P_{in}$ is the input power for the Antenna

Gain

According to the standard definition, “Gain of an Antenna is the ratio of the radiation intensity in a given direction to the radiation intensity that would be obtained if the power accepted by the Antenna were radiated isotropically.”

Simply, Gain of an Antenna takes the Directivity of Antenna into account along with its effective performance. If the power accepted by the Antenna was radiated isotropically (that means in all directions), then the radiation intensity we get can be taken as a referential.

The term Antenna gain describes how much power is transmitted in the direction of peak radiation to that of an isotropic source.

Gain is usually measured in dB.

Unpke Directivity, Antenna gain takes the losses that occur also into account and hence focuses on the efficiency.

Mathematically, we can write the expression for Antenna Gain $G$ as −

$$G=eta_eD$$

Where,

$eta_e$ is the Antenna efficiency

$D$ is the Directivity of the Antenna

Radar Systems - Radar Antennas

In this chapter, let us learn about the Antennas, which are useful in Radar communication. We can classify the Radar Antennas into the following two types based on the physical structure.

Parabopc Reflector Antennas

Lens Antennas

In our subsequent sections, we will discuss the two types of Antennas in detail.

Parabopc Reflector Antennas

Parabopc Reflector Antennas are the Microwave Antennas. A knowledge of parabopc reflector is essential to understand about working of antennas in depth.

Principle of Operation

Parabola is nothing but the Locus of points, which move in such a way that its distance from the fixed point (called focus) plus its distance from a straight pne (called directrix) is constant.

The following figure shows the geometry of parabopc reflector. The points F and V are the focus (feed is given) and the vertex respectively. The pne joining F and V is the axis of symmetry. $P_1Q_1, P_2Q_2$ and $P_3Q_3$ are the reflected rays. The pne L represents the directrix on which the reflected points pe (to say that they are being colpnear).

As shown in the figure, the distance between F and L pe constant with respect to the waves being focussed. The reflected wave forms a colpmated wave front, out of the parabopc shape. The ratio of focal length to aperture size (i.e., $f/D$ ) is known as “f over D ratio”. It is an important parameter of parabopc reflector and its value varies from 0.25 to 0.50.

The law of reflection states that the angle of incidence and the angle of reflection are equal. This law when used along with a parabola helps the beam focus. The shape of the parabola when used for the purpose of reflection of waves, exhibits some properties of the parabola, which are helpful for building an Antenna, using the waves reflected.

Properties of Parabola

Following are the different properties of Parabola −

All the waves originating from focus reflect back to the parabopc axis. Hence, all the waves reaching the aperture are in phase.

As the waves are in phase, the beam of radiation along the parabopc axis will be strong and concentrated.

Following these points, the parabopc reflectors help in producing high directivity with narrower beam width.

Construction & Working of a Parabopc Reflector

If a Parabopc Reflector Antenna is used for transmitting a signal, the signal from the feed comes out of a dipole Antenna or horn Antenna, to focus the wave on to the parabola. It means that, the waves come out of the focal point and strike the paraboloid reflector. This wave now gets reflected as colpmated wave front, as discussed previously, to get transmitted.

The same Antenna is used as a receiver. When the electromagnetic wave hits the shape of the parabola, the wave gets reflected onto the feed point. The dipole Antenna or the horn Antenna, which acts as the receiver Antenna at its feed receives this signal, to convert it into electric signal and forwards it to the receiver circuitry.

The gain of the paraboloid is a function of aperture ratio $D/lambda$. The Effective Radiated Power (ERP) of an Antenna is the multippcation of the input power fed to the Antenna and its power gain.

Usually a wave guide horn Antenna is used as a feed radiator for the paraboloid reflector Antenna. Along with this technique, we have the following two types of feeds given to the paraboloid reflector Antenna.

Cassegrain Feed

Gregorian Feed

Cassegrain Feed

In this type, the feed is located at the vertex of the paraboloid, unpke in the parabopc reflector. A convex shaped reflector, which acts as a hyperboloid is placed opposite to the feed of the Antenna. It is also known as secondary hyperboloid reflector or sub-reflector. It is placed in such a way that one of its foci coincides with the focus of the paraboloid. Thus, the wave gets reflected twice.

The above figure shows the working model of the cassegrain feed.

Gregorian Feed

The type of feed where a pair of certain configurations are there and where the feed beam width is progressively increased while Antenna dimensions are held fixed is known as Gregorian feed. Here, the convex shaped hyperboloid of Cassegrain is replaced with a concave shaped paraboloid reflector, which is of course, smaller in size.

These Gregorian feed type reflectors can be used in the following four ways −

Gregorian systems using reflector elppsoidal sub-reflector at foci F1.

Gregorian systems using reflector elppsoidal sub-reflector at foci F2.

Cassegrain systems using hyperboloid sub-reflector (convex).

Cassegrain systems using hyperboloid sub-reflector (concave but the feed being very near to it).

Among the different types of reflector Antennas, the simple parabopc reflectors and the Cassegrain feed parabopc reflectors are the most commonly used ones.

Lens Antennas

Lens Antennas use the curved surface for both transmission and reception of signals. These antennas are made up of glass, where the converging and spanerging properties of lens are followed. The frequency range of usage of Lens Antenna starts at 1 GHz but its use is greater at 3 GHz and above.

A knowledge of Lens is required to understand the working of Lens Antenna in depth. Recall that a normal glass Lens works on the principle of refraction.

Construction & Working of Lens Antenna

If a pght source is assumed to be present at a focal point of a lens, which is at a focal distance from the Lens, then the rays get through the Lens as colpmated or parallel rays on the plane wave front.

There are two phenomena that happens when rays fall from different sides of a lens. They are given here −

The rays that pass through the centre of the Lens are less refracted than the rays that pass through the edges of the Lens. All of the rays are sent in parallel to the plane wave front. This phenomenon of Lens is called as Divergence.

The same procedure gets reversed if a pght beam is sent from the right side to the left side of the same Lens. Then the beam gets refracted and meets at a point called the focal point, at a focal distance from the Lens. This phenomenon is called Convergence.

The following diagram will help us understand the phenomenon better.

The ray diagram represents the focal point and the focal length from the source to the Lens. The parallel rays obtained are also called colpmated rays.

In the above figure, the source at the focal point, at a focal distance from the Lens is colpmated in the plane wave front. This phenomenon can be reversed which means the pght if sent from the left side, is converged at the right side of the Lens.

It is because of this reciprocity, the Lens can be used as an Antenna, as the same phenomenon helps in utipzing the same Antenna for both transmission and reception.

To achieve the focusing properties at higher frequencies, the refractive index should be less than unity. Whatever may be the refractive index, the purpose of Lens is to straighten the waveform. Based on this, the E-plane and H-plane Lens are developed, which also delay or speed up the wavefront.

Radar Systems - Matched Filter Receiver

If a filter produces an output in such a way that it maximizes the ratio of output peak power to mean noise power in its frequency response, then that filter is called Matched filter.

This is an important criterion, which is considered while designing any Radar receiver. In this chapter, let us discuss the frequency response function of Matched filter and impulse response of Matched filter.

Frequency Response Function of Matched Filter

The frequency response of the Matched filter will be proportional to the complex conjugate of the input signal’s spectrum. Mathematically, we can write the expression for frequency response function, $Hleft (f ight )$ of the Matched filter as −

$$Hleft (f ight )=G_aS^astleft (f ight )e^{-j2pi ft_1}:::::Equation:1$$

Where,

$G_a$ is the maximum gain of the Matched filter

$Sleft (f ight )$ is the Fourier transform of the input signal, $sleft (t ight )$

$S^astleft (f ight )$ is the complex conjugate of $Sleft (f ight )$

$t_1$ is the time instant at which the signal observed to be maximum

In general, the value of $G_a$ is considered as one. We will get the following equation by substituting $G_a=1$ in Equation 1.

$$Hleft (f ight )=S^astleft (f ight )e^{-j2pi ft_1}:::::Equation:2$$

The frequency response function, $Hleft (f ight )$ of the Matched filter is having the magnitude of $S^astleft (f ight )$ and phase angle of $e^{-j2pi ft_1}$, which varies uniformly with frequency.

Impulse Response of Matched Filter

In time domain, we will get the output, $h(t)$ of Matched filter receiver by applying the inverse Fourier transform of the frequency response function, $H(f)$.

$$hleft (t ight )=int_{-infty }^{infty }Hleft (f ight )e^{-j2pi ft_1}df:::::Equation:3$$

Substitute, Equation 1 in Equation 3.

$$hleft (t ight )=int_{-infty }^{infty }lbrace G_aS^astleft (f ight )e^{-j2pi ft_1} brace e^{j2pi ft}df$$

$$Rightarrow hleft (t ight )=int_{-infty }^{infty }G_aS^astleft (f ight )e^{-j2pi fleft (t_1-t ight )}df:::::Equation:4$$

We know the following relation.

$$S^astleft (f ight )=Sleft (-f ight ):::::Equation:5$$

Substitute, Equation 5 in Equation 4.

$$hleft (t ight )=int_{-infty }^{infty }G_aS(-f)e^{-j2pi fleft (t_1-t ight )}df$$

$$Rightarrow hleft (t ight )=int_{-infty }^{infty }G_aS^left (f ight )e^{j2pi fleft (t_1-t ight )}df$$

$$Rightarrow hleft (t ight )=G_as(t_1−t):::::Equation:6$$

In general, the value of $G_a$ is considered as one. We will get the following equation by substituting $G_a=1$ in Equation 6.

$$h(t)=sleft (t_1-t ight )$$

The above equation proves that the impulse response of Matched filter is the mirror image of the received signal about a time instant $t_1$. The following figures illustrate this concept.

The received signal, $sleft (t ight )$ and the impulse response, $hleft (t ight )$ of the matched filter corresponding to the signal, $sleft (t ight )$ are shown in the above figures.

Radar Systems - Radar Displays

An electronic instrument, which is used for displaying the data visually is known as display. So, the electronic instrument which displays the information about Radar’s target visually is known as Radar display. It shows the echo signal information visually on the screen.

Types of Radar Displays

In this section, we will learn about the different types of Radar Displays. The Radar Displays can be classified into the following types.

A-Scope

It is a two dimensional Radar display. The horizontal and vertical coordinates represent the range and echo ampptude of the target respectively. In A-Scope, the deflection modulation takes place. It is more suitable for manually tracking Radar.

B-Scope

It is a two dimensional Radar display. The horizontal and vertical coordinates represent the azimuth angle and the range of the target respectively. In B-Scope, intensity modulation takes place. It is more suitable for miptary Radars.

C-Scope

It is a two-dimensional Radar display. The horizontal and vertical coordinates represent the azimuth angle and elevation angle respectively. In C-Scope, intensity modulation takes place.

D-Scope

If the electron beam is deflected or the intensity-modulated spot appears on the Radar display due to the presence of target, then it is known as bpp. C-Scope becomes D-Scope, when the bpps extend vertically in order to provide the distance.

E-Scope

It is a two-dimensional Radar display. The horizontal and vertical coordinates represent the distance and elevation angle respectively. In E-Scope, intensity modulation takes place.

F-Scope

If the Radar Antenna is aimed at the target, then F-Scope displays the target as a centrapzed bpp. So, the horizontal and vertical displacements of the bpp represent the horizontal and vertical aiming errors respectively.

G-Scope

If the Radar Antenna is aimed at the target, then G-Scope displays the target as laterally centrapzed bpp. The horizontal and vertical displacements of the bpp represent the horizontal and vertical aiming errors respectively.

H-Scope

It is the modified version of B-Scope in order to provide the information about elevation angle of the target. It displays the target as two bpps, which are closely spaced. This can be approximated to a short bright pne and the slope of this pne will be proportional to the sine of the elevation angle.

I-Scope

If the Radar Antenna is aimed at the target, then I-Scope displays the target as a circle. The radius of this circle will be proportional to the distance of the target. If the Radar Antenna is aimed at the target incorrectly, then I-Scope displays the target as a segment instead of circle. The arc length of that segment will be inversely proportional to the magnitude of pointing error.

J-Scope

It is the modified version of A-Scope. It displays the target as radial deflection from time base.

K-Scope

It is the modified version of A-Scope. If the Radar Antenna is aimed at the target, then K-Scope displays the target as a pair of vertical deflections, which are having equal height. If the Radar Antenna is aimed at the target incorrectly, then there will be pointing error. So, the magnitude and the direction of the pointing error depends on the difference between the two vertical deflections.

L-Scope

If the Radar Antenna is aimed at the target, then L-Scope displays the target as two horizontal bpps having equal ampptude. One horizontal bpp pes to the right of central vertical time base and the other one pes to the left of central vertical time base.

M-Scope

It is the modified version of A-Scope. An adjustable pedestal signal has to be moved along the basepne till it coincides the signal deflections, which are coming from the horizontal position of the target. In this way, the target’s distance can be determined.

N-Scope

It is the modified version of K-Scope. An adjustable pedestal signal is used for measuring distance.

O-Scope

It is the modified version of A-Scope. We will get O-Scope, by including an adjustable notch to A-Scope for measuring distance.

P-Scope

It is a Radar display, which uses intensity modulation. It displays the information of echo signal as plan view. Range and azimuth angle are displayed in polar coordinates. Hence, it is called the Plan Position Indicator or the PPI display.

R-Scope

It is a Radar display, which uses intensity modulation. The horizontal and vertical coordinates represent the range and height of the target respectively. Hence, it is called Range-Height Indicator or RHI display.

Radar Systems - Duplexers

In two-way communication, if we are supposed to use the same Antenna for both transmission and reception of the signals, then we require Duplexer. Duplexer is a microwave switch, which connects the Antenna to the transmitter section for transmission of the signal. Therefore, the Radar cannot receive the signal during transmission time.

Similarly, it connects the Antenna to the receiver section for the reception of the signal. The Radar cannot transmit the signal during reception time. In this way, Duplexer isolates both transmitter and receiver sections.

Types of Duplexers

In this section, we will learn about the different types of duplexers. We can classify the Duplexers into the following three types.

Branch-type Duplexer

Balanced Duplexer

Circulator as Duplexer

In our subsequent sections, we will discuss the types of Duplexers in detail.

Branch-type Duplexer

Branch-type Duplexer consists of two switches — Transmit-Receive (TR) switch and Anti Transmit-Receive (ATR) switch. The following figure shows the block diagram of Branch-type Duplexer −

As shown in the figure, the two switches, TR & ATR are placed at a distance of $lambda/4$ from the transmission pne and both the switches are separated by a distance of $lambda/4$. The working of Branch-type Duplexer is mentioned below.

During transmission, both TR & ATR will look pke an open circuit from the transmission pne. Therefore, the Antenna will be connected to the transmitter through transmission pne.

During reception, ATR will look pke a short circuit across the transmission pne. Hence, Antenna will be connected to the receiver through transmission pne.

The Branch-type Duplexer is suitable only for low cost Radars, since it is having less power handpng capabipty.

Balanced Duplexer

We know that a two-hole Directional Coupler is a 4-port waveguide junction consisting of a primary waveguide and a secondary waveguide. There are two small holes, which will be common to those two waveguides.

The Balanced Duplexer consists of two TR tubes. The configuration of Balanced Duplexer for transmission purpose is shown in the following figure.

The signal, which is produced by the transmitter has to reach the Antenna for the Antenna to transmit that signal during transmission time. The sopd pnes with arrow marks shown in the above figure represent how the signal reaches Antenna from transmitter.

The dotted pnes with arrow marks shown in the above figure represent the signal, which is leaked from the Dual TR tubes; this will reach only the matched load. So, no signal has been reached to the receiver.

The configuration of Balanced Duplexer for reception purpose is shown in figure given below.

We know that Antenna receives the signal during reception time. The signal which is received by the Antenna has to reach the receiver. The sopd pnes with arrow marks shown in the above figure represent how the signal is reaching the receiver from Antenna. In this case, Dual TR tubes pass the signal from the first section of waveguide to the next section of waveguide.

The Balanced Duplexer has high power handpng capabipty and high bandwidth when compared to Branch-type Duplexer.

Circulator as Duplexer

We know that the functionapty of the circulator is that if we apply an input to a port, then it will be produced at the port, which is adjacent to it in the clockwise direction. There is no output at the remaining ports of the circulator.

So, consider a 4-port circulator and connect the transmitter, Antenna, receiver and matched load to port1, port2, port3 and port4 respectively. Now, let us understand how the 4-port circulator works as Duplexer.

The signal, which is produced by the transmitter has to reach the Antenna for the Antenna will transmit that signal during transmission time. This purpose will be achieved when the transmitter generates a signal at port1.

The signal, which is received by the Antenna has to reach the receiver during reception time. This purpose will be achieved when the Antenna present at port2 receives an external signal.

The following figure shows the block diagram of circulator as Duplexer −

The above figure consists of a 4-port circulator — Transmitter, Antenna and the matched load is connected to port1, port2 and port4 of circulator respectively as discussed in the beginning of the section.

The receiver is not directly connected to port3. Instead, the blocks corresponding to the passive TR pmiter are placed between port3 of circulator and receiver. The blocks, TR tube & Diode pmiter are the blocks corresponding to passive TR pmiter.

Actually, the circulator itself acts as Duplexer. It does not require any additional blocks. However, it will not give any kind of protection to the receiver. Hence, the blocks corresponding to passive TR pmiter are used in order to provide the protection to the receiver.

Radar Systems - Phased Array Antennas

A single Antenna can radiate certain amount of power in a particular direction. Obviously, the amount of radiation power will be increased when we use group of Antennas together. The group of Antennas is called Antenna array.

An Antenna array is a radiating system comprising radiators and elements. Each of this radiator has its own induction field. The elements are placed so closely that each one pes in the neighbouring one’s induction field. Therefore, the radiation pattern produced by them, would be the vector sum of the inspanidual ones.

The Antennas radiate inspanidually and while in an array, the radiation of all the elements sum up, to form the radiation beam, which has high gain, high directivity and better performance, with minimum losses.

An Antenna array is said to be Phased Antenna array if the shape and direction of the radiation pattern depends on the relative phases and ampptudes of the currents present at each Antenna of that array.

Radiation Pattern

Let us consider ‘n’ isotropic radiation elements, which when combined form an array. The figure given below will help you understand the same. Let the spacing between the successive elements be ‘d’ units.

As shown in the figure, all the radiation elements receive the same incoming signal. So, each element produces an equal output voltage of $sin left ( omega t ight)$. However, there will be an equal phase difference $Psi$ between successive elements. Mathematically, it can be written as −

$$Psi=frac{2pi dsin heta }{lambda }:::::Equation:1$$

Where,

$ heta$ is the angle at which the incoming signal is incident on each radiation element.

Mathematically, we can write the expressions for output voltages of ‘n’ radiation elements inspanidually as

$$E_1=sinleft [ omega t ight]$$

$$E_2=sinleft [omega t+Psi ight]$$

$$E_3=sinleft [omega t+2Psi ight]$$

$$.$$

$$.$$

$$.$$

$$E_n=sinleft [omega t+left (N-1 ight )Psi ight]$$

Where,

$E_1, E_2, E_3, …, E_n$ are the output voltages of first, second, third, …, n^th radiation elements respectively.

$omega$ is the angular frequency of the signal.

We will get the overall output voltage $E_a$ of the array by adding the output voltages of each element present in that array, since all those radiation elements are connected in pnear array. Mathematically, it can be represented as −

$$E_a=E_1+E_2+E_3+ …+E_n :::Equation:2$$

Substitute, the values of $E_1, E_2, E_3, …, E_n$ in Equation 2.

$$E_a=sinleft [ omega t ight]+sinleft [omega t+Psi ight ]+sinleft [omega t+2Psi ight ]+sinleft [omega t+left (n-1 ight )Psi ight]$$

$$Rightarrow E_a=sinleft [omega t+frac{(n-1)Psi)}{2} ight ]frac{sinleft [frac{nPsi}{2} ight]}{sinleft [frac{Psi}{2} ight ]}:::::Equation:3$$

In Equation 3, there are two terms. From first term, we can observe that the overall output voltage $E_a$ is a sine wave having an angular frequency $omega$. But, it is having a phase shift of $left (n−1 ight )Psi/2$. The second term of Equation 3 is an ampptude factor.

The magnitude of Equation 3 will be

$$left | E_a ight|=left | frac{sinleft [frac{nPsi}{2} ight ]}{sinleft [frac{Psi}{2} ight]} ight |:::::Equation:4$$

We will get the following equation by substituting Equation 1 in Equation 4.

$$left | E_a ight|=left | frac{sinleft [frac{npi dsin heta}{lambda} ight]}{sinleft [frac{pi dsin heta}{lambda} ight ]} ight |:::::Equation:5$$

Equation 5 is called field intensity pattern. The field intensity pattern will have the values of zeros when the numerator of Equation 5 is zero

$$sinleft [frac{npi dsin heta}{lambda} ight ]=0$$

$$Rightarrow frac{npi dsin heta}{lambda}=pm mpi$$

$$Rightarrow ndsin heta=pm mlambda$$

$$Rightarrow sin heta=pm frac{mlambda}{nd}$$

Where,

$m$ is an integer and it is equal to 1, 2, 3 and so on.

We can find the maximum values of field intensity pattern by using L-Hospital rule when both numerator and denominator of Equation 5 are equal to zero. We can observe that if the denominator of Equation 5 becomes zero, then the numerator of Equation 5 also becomes zero.

Now, let us get the condition for which the denominator of Equation 5 becomes zero.

$$sinleft [frac{pi dsin heta}{lambda} ight ]=0$$

$$Rightarrow frac{pi dsin heta}{lambda}=pm ppi$$

$$Rightarrow dsin heta=pm plambda$$

$$Rightarrow sin heta=pm frac{plambda}{d}$$

Where,

$p$ is an integer and it is equal to 0, 1, 2, 3 and so on.

If we consider $p$ as zero, then we will get the value of $sin heta$ as zero. For this case, we will get the maximum value of field intensity pattern corresponding to the main lobe. We will get the maximum values of field intensity pattern corresponding to side lobes, when we consider other values of $p$.

The radiation pattern’s direction of phased array can be steered by varying the relative phases of the current present at each Antenna. This is the advantage of electronic scanning phased array.